Each item of this array is some number.
var items = Array(523,3452,334,31, ...5346);
How do I replace some number in with array with a new on
The Array.indexOf()
method will replace the first instance. To get every instance use Array.map()
:
a = a.map(function(item) { return item == 3452 ? 1010 : item; });
Of course, that creates a new array. If you want to do it in place, use Array.forEach()
:
a.forEach(function(item, i) { if (item == 3452) a[i] = 1010; });
The easiest way is this.
var items = Array(523,3452,334,31, 5346);
var replaceWhat = 3452, replaceWith = 1010;
if ( ( i = items.indexOf(replaceWhat) ) >=0 ) items.splice(i, 1, replaceWith);
console.log(items);
>>> (5) [523, 1010, 334, 31, 5346]
If you want a simple sugar sintax oneliner you can just:
(elements = elements.filter(element => element.id !== updatedElement.id)).push(updatedElement);
Like:
let elements = [ { id: 1, name: 'element one' }, { id: 2, name: 'element two'} ];
const updatedElement = { id: 1, name: 'updated element one' };
If you don't have id you could stringify the element like:
(elements = elements.filter(element => JSON.stringify(element) !== JSON.stringify(updatedElement))).push(updatedElement);
You can edit any number of the list using indexes
for example :
items[0] = 5;
items[5] = 100;
Replacement can be done in one line:
var items = Array(523, 3452, 334, 31, 5346);
items[items.map((e, i) => [i, e]).filter(e => e[1] == 3452)[0][0]] = 1010
console.log(items);
Or create a function to reuse:
Array.prototype.replace = function(t, v) {
if (this.indexOf(t)!= -1)
this[this.map((e, i) => [i, e]).filter(e => e[1] == t)[0][0]] = v;
};
//Check
var items = Array(523, 3452, 334, 31, 5346);
items.replace(3452, 1010);
console.log(items);
Here's a one liner. It assumes the item will be in the array.
var items = [523, 3452, 334, 31, 5346]
var replace = (arr, oldVal, newVal) => (arr[arr.indexOf(oldVal)] = newVal, arr)
console.log(replace(items, 3452, 1010))