let timeFont = [NSFontAttributeName:UIFont(name: \"Voyage\", size: 20.0)]
var attrString3 = NSAttributedString(\"(Time)\", attributes : timeFont); // <--- compile
There are two reasons your code is failing to compile:
NSAttributedString
that you want to use now requires the explicit labeling of the string
parameterUIFont
initializer that you are using now returns an optional (i.e., UIFont?
), which needs to be unwrapped before you pass it in the attributes dictionary.Try this instead:
let font = UIFont(name: "Voyage", size: 20.0) ?? UIFont.systemFontOfSize(20.0)
let attrs = [NSFontAttributeName : font]
var attrString3 = NSAttributedString(string: "(Time)", attributes: attrs)
Note the use of the new coalescing operator ??
. This unwraps the optional Voyage font, but falls back to the System Font if Voyage is unavailable (which seems to be the case in the Playground). This way, you get your attributed string regardless, even if your preferred font can't be loaded.
Xcode 6.1 comes with Swift 1.1 that supports constructors that can fail. UIFont
initialisation can fail and return nil
. Also use string:
when creating NSAttributedString
:
if let font = UIFont(name: "Voyage", size: 20.0) {
let timeFont = [NSFontAttributeName:font]
var attrString3 = NSAttributedString(string: "(Time)", attributes : timeFont)
}