How do I use floating point number literals when using generic types?

Question

Regular float literals do not work:

extern crate num_traits;

use num_traits::float::Float;

fn scale_float(x: T) -> T {
    x * 0.54
}

f         


        

Answer 1

In certain cases, you can add a restriction that the generic type must be able to be multiplied by the type of the literal. Here, we allow any type that can be multiplied by a f64 so long as it produces the output type of T via the trait bound Mul<f64, Output = T>:

use num_traits::float::Float; // 0.2.6
use std::ops::Mul;

fn scale_float<T>(x: T) -> T
where
    T: Float + Mul<f64, Output = T>,
{
    x * 0.54
}

fn main() {
    let a: f64 = scale_float(1.23);
}

This may not work directly for the original problem, but it might depending on what concrete types you need to work with.

Answer 2

You can't create a Float from a literal directly. I suggest an approach similar to the FloatConst trait:

trait SomeDomainSpecificScaleFactor {
    fn factor() -> Self;
}

impl SomeDomainSpecificScaleFactor for f32 {
    fn factor() -> Self {
        0.54
    }
}

impl SomeDomainSpecificScaleFactor for f64 {
    fn factor() -> Self {
        0.54
    }
}

fn scale_float<T: Float + SomeDomainSpecificScaleFactor>(x: T) -> T {
    x * T::factor()
}

(link to playground)

Answer 3

Use the FromPrimitive trait:

use num_traits::{cast::FromPrimitive, float::Float};

fn scale_float<T: Float + FromPrimitive>(x: T) -> T {
    x * T::from_f64(0.54).unwrap()
}

Or the standard library From / Into traits

fn scale_float<T>(x: T) -> T
where
    T: Float,
    f64: Into<T>
{
    x * 0.54.into()
}

See also:

• How do I use number literals with the Integer trait from the num crate?