Use value of variable in lambda expression [duplicate]

Answer 1

Ugly, but one way:

for i in range(4)
    b.append(lambda x, copy=i: x**copy)

You might prefer

def raiser(power):
    return lambda x: x**power

for i in range(4)
    b.append(raiser(i))

(All code untested.)

Answer 2

Define a factory

def power_function_factory(value):
    def new_power_function(base):
        return base ** value
    return new_power_function

b = []
for i in range(4):
    b.append(power_function_factory(i))

or

b = [power_function_factory(i) for i in range(4)]

Answer 3

b=[]
f=(lambda p:(lambda x:x**p))
for i in range(4):
   b.append(f(i))
for g in b:
   print g(2)