Creating and appending detached elements with d3.create

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隐瞒了意图╮

Let\'s say I create a simple graphic like this:

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太阳男子

2020-11-29 12:59

Just namespace it:

const detachedG = d3.create('svg:g');

Here is the code with that change:

<!doctype html>
<html lang="en">
    <head><script src="https://d3js.org/d3.v5.min.js"></script></head>
    <body>
        <svg></svg>
        <script>
            const svg = d3.select('svg');
            const g = svg.append('g');

            const detachedG = d3.create('svg:g');
            detachedG.selectAll('g')
                .data([5,10,20,40])
                .enter()
                .append('rect')
                .attr('fill', 'green')
                .attr('x', d => d)
                .attr('y', d => d)
                .attr('height', d => d)
                .attr('width', d => d);

            g.append(() => detachedG.node());
        </script>
    </body>
</html>

Explanation

When appending SVG elements with the append() method, 98.47% of D3 programmers don't use namespaces (source: Fakedata Inc.). Therefore, instead of:

selection.append("svg:rect")

We normally just do:

selection.append("rect")

So, why do you need a namespace here?

Internally, d3.create uses d3.creator calling it with document.documentElement:

export default function(name) {
    return select(creator(name).call(document.documentElement));
}

That changes the this for the d3.creator method. We normally don't use namespaces when we create SVG elements using append (which internally uses d3.creator), since:

If no namespace is specified, the namespace will be inherited from the parent element.

However, because of the use of document.documentElement as this, the namespace becomes necessary in this case.

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