I\'m trying to write a procedure in prolog where if L1 = [1,2,3] and L2 = [4,5,6] then L3 = [1,4,2,5,3,6]
so shuffle([1,2,3],[4,5,6],[1,4,2,5,3,6])
shuffle([], B, B).
shuffle([H|A], B, [H|S]) :- shuffle(B, A, S).
In this kind of problems, usually the difficult part is not Prolog but identifying the simplest recursive relation that solves it.
Here's the simple solution:
shuffle([], [], []).
shuffle([X|Xs], [Y|Ys], [X,Y|Zs]) :-
shuffle(Xs,Ys,Zs).
Generalizing this to handle list of unequal length is a matter of changing the base case into:
shuffle(Xs, [], Xs).
shuffle([], Ys, Ys).
although that may generate duplicate solutions. Those can be fixed with a cut if you don't mind the predicate being "one-way".
(Though I still think you should call this flatzip
or interlace
instead of shuffle
.)