PHP: strtotime is returning false for a future date?

Question

here are some debug expressions i put into eclipse, if you don\'t believe me:

\"strtotime(\"2110-07-16 10:07:47\")\" = (boolean) false    
\"strtotime(\"2110         


        

Answer 1

You cant convert dates that occur after the unix time rollover (2038)

Answer 2

Simple replacement of strtotime

$date = '2199-12-31T08:00:00.000-06:00';

echo date('Y-m-d', strtotime($date)); // fails with 1970 result

echo date_format(  date_create($date) , 'Y-m-d'); // works perfect with 5.2+

Actual post here.

Answer 3

From the PHP manual:

The valid range of a timestamp is typically from Fri, 13 Dec 1901 20:45:54 GMT to Tue, 19 Jan 2038 03:14:07 GMT. (These are the dates that correspond to the minimum and maximum values for a 32-bit signed integer). However, before PHP 5.1.0 this range was limited from 01-01-1970 to 19-01-2038 on some systems (e.g. Windows).

See also: Year 2038 problem - Wikipedia

Answer 4

Try to keep it before Tue, 19 Jan 2038 03:14:07 UTC, when the unix timestamp epoch for 32 bit systems rolls over!

It's even described in the manual at http://php.net/strtotime

edit: Just tested: It's fixed by installing a 64 bit OS and appropriate 64 bit version of php. I guess we have time enough to fix a reincarnated millenium bug:

$one = strtotime("9999-12-31 23:59:59");  
$two = strtotime("10000-01-01 00:00:00");
var_dump($one);
var_dump($two);

int(253402297199)
bool(false)

Answer 5

If you want to work with dates that fall outside the 32-bit integer date range, then use PHP's dateTime objects

try {
    $date = new DateTime('2110-07-16 10:07:47');
} catch (Exception $e) {
    echo $e->getMessage();
    exit(1);
}

echo $date->format('Y-m-d');