How to execute a stored procedure in php using sqlsrv and “?” style parameters

Question

I\'ve looked over several other questions that seem (from the titles) the same as this. However, my case is a bit different.

The following works (i.e. I get \"succes

Answer 1

The user contributions on the php.net have a write up on how to execute a stored procedure using the sqlsrv-prepare.

In case that is removed from the php.net user contributions in the future here is what it had(has) listed:

$procedure_params = array(
array(&$myparams['Item_ID'], SQLSRV_PARAM_OUT),
array(&$myparams['Item_Name'], SQLSRV_PARAM_OUT)
);
// EXEC the procedure, {call stp_Create_Item (@Item_ID = ?, @Item_Name = ?)} seems to fail with various errors in my experiments
$sql = "EXEC stp_Create_Item @Item_ID = ?, @Item_Name = ?";
$stmt = sqlsrv_prepare($conn, $sql, $procedure_params);

Here's the manual's page, http://php.net/manual/en/function.sqlsrv-prepare.php

Answer 2

This is a follow up to the answer by @chris85.

It's worth noting here that once the statement is prepared, you need to execute it:

$sql = "EXEC stp_Create_Item @Item_ID = ?, @Item_Name = ?";
$stmt = sqlsrv_prepare($conn, $sql, $procedure_params);
if (!sqlsrv_execute($stmt)) {
    echo "Your code is fail!";
    die;
}
while($row = sqlsrv_fetch_array($stmt)){
    //Stuff
}

sqlsrv_execute() only returns true/false. If you want to parse the data returned by the stored procedure you can process it just like the result from sqlsrv_query().

If you forget the sqlsrv_execute() you'll get an error saying that the result has to be executed before it can be used.

Answer 3

Make sure you set this or you will always get errors returned if the stored procedure has messages being returned.

sqlsrv_configure('WarningsReturnAsErrors',0);

//Full working code below

$sql = "{call NameOfDatabase.NameOfOwner.StoredProcedureName(?,?)}";

$params = array($param1, $param2); 

if ($stmt = sqlsrv_prepare($conn, $sql, $params)) {
    echo "Statement prepared.<br><br>\n";  

} else {  
    echo "Statement could not be prepared.\n";  
    die(print_r(sqlsrv_errors(), true));  
} 

if( sqlsrv_execute( $stmt ) === false ) {

    die( print_r( sqlsrv_errors(), true));

}else{

    print_r(sqlsrv_fetch_array($stmt));

}