I have to create a Shell Script wherein one of the parameters will be the date in the format dd/mm/yyyy. My question is, how can I check if the Date passed as parameter real
Simplest way for dd/mm/yyyy
exactly in Bash is:
if [[ $1 == [0-3][0-9]/[0-1][0-9]/[0-9][0-9][0-9][0-9] ]]
Or
if [[ $1 =~ ^[0-3][0-9]/[0-1][0-9]/[0-9]{4}$ ]]
Here's a function to do some data validation this:
# Script expecting a Date parameter in MM-DD-YYYY format as input
verifyInputDate(){
echo ${date} | grep '^[0-9][0-9]-[0-9][0-9]-[0-9][0-9][0-9][0-9]$'
if [ $? -eq 0 ]; then
echo "Date is valid"
else
echo "Date is not valid"
fi
}
Use date
date "+%d/%m/%Y" -d "09/99/2013" > /dev/null 2>&1
is_valid=$?
If you do not get 0 then date is in invalid format.
This function expects 2 strings,a format string, a date string
The format string uses the codes from the date command but does not include the '+'
The function returns 0 if the provided date matches the given format, otherwise it returns 1
Code (my_script.sh)
#!/bin/bash
datecheck() {
local format="$1" d="$2"
[[ "$(date "+$format" -d "$d" 2>/dev/null)" == "$d" ]]
}
date_test="$1"
echo $date_test
if datecheck "%d %b %Y" "$date_test"; then
echo OK
else
echo KO
fi
Output
$ ./my_script.sh "05 Apr 2020"
05 Apr 2020
OK
$ ./my_script.sh "foo bar"
foo bar
KO
First, check the form of the input using the regex. Then use awk to switch to mm/dd/yyyy and use date to validate. You can use the following expression in your if
statement:
echo "$1" | egrep -q '^[0-3][0-9]/[0-1][0-9]/[0-9]{4}$' && date -d "$(echo "$1" | awk 'BEGIN{FS=OFS="/"}{print $2"/"$1"/"$3}')" >/dev/null 2>&1
#! /bin/bash
isDateInvalid()
{
DATE="${1}"
# Autorized separator char ['space', '/', '.', '_', '-']
SEPAR="([ \/._-])?"
# Date format day[01..31], month[01,03,05,07,08,10,12], year[1900..2099]
DATE_1="((([123][0]|[012][1-9])|3[1])${SEPAR}(0[13578]|1[02])${SEPAR}(19|20)[0-9][0-9])"
# Date format day[01..30], month[04,06,09,11], year[1900..2099]
DATE_2="(([123][0]|[012][1-9])${SEPAR}(0[469]|11)${SEPAR}(19|20)[0-9][0-9])"
# Date format day[01..28], month[02], year[1900..2099]
DATE_3="(([12][0]|[01][1-9]|2[1-8])${SEPAR}02${SEPAR}(19|20)[0-9][0-9])"
# Date format day[29], month[02], year[1904..2096]
DATE_4="(29${SEPAR}02${SEPAR}(19|20(0[48]|[2468][048]|[13579][26])))"
# Match the date in the Regex
if ! [[ "${DATE}" =~ "^(${DATE_1}|${DATE_2}|${DATE_3}|${DATE_4})$" ]]
then
echo -e "ERROR - '${DATE}' invalid!"
else
echo "${DATE} is valid"
fi
}
echo
echo "Exp 1: "`isDateInvalid '12/13/3000'`
echo "Exp 2: "`isDateInvalid '12/11/2014'`
echo "Exp 3: "`isDateInvalid '12 01 2000'`
echo "Exp 4: "`isDateInvalid '28-02-2014'`
echo "Exp 5: "`isDateInvalid '12_02_2002'`
echo "Exp 6: "`isDateInvalid '12.10.2099'`
echo "Exp 7: "`isDateInvalid '31/11/2000'`