Converting long string of binary to hex c#

Question

I\'m looking for a way to convert a long string of binary to a hex string.

the binary string looks something like this \"01100110100101110010011101010111001101

Answer 1

Considering four bits can be expressed by one hex value, you can simply go by groups of four and convert them seperately, the value won't change that way.

string bin = "11110110";

int rest = bin.Length % 4;
bin = bin.PadLeft(rest, '0'); //pad the length out to by divideable by 4

string output = "";

for(int i = 0; i <= bin.Length - 4; i +=4)
{
    output += string.Format("{0:X}", Convert.ToByte(bin.Substring(i, 4), 2));
}

Answer 2

I came up with this method. I am new to programming and C# but I hope you will appreciate it:

static string BinToHex(string bin)
{
    StringBuilder binary = new StringBuilder(bin);
    bool isNegative = false;
    if (binary[0] == '-')
    {
        isNegative = true;
        binary.Remove(0, 1);
    }

    for (int i = 0, length = binary.Length; i < (4 - length % 4) % 4; i++) //padding leading zeros
    {
        binary.Insert(0, '0');
    }

    StringBuilder hexadecimal = new StringBuilder();
    StringBuilder word = new StringBuilder("0000");
    for (int i = 0; i < binary.Length; i += 4)
    {
        for (int j = i; j < i + 4; j++)
        {
            word[j % 4] = binary[j];
        }

        switch (word.ToString())
        {
            case "0000": hexadecimal.Append('0'); break;
            case "0001": hexadecimal.Append('1'); break;
            case "0010": hexadecimal.Append('2'); break;
            case "0011": hexadecimal.Append('3'); break;
            case "0100": hexadecimal.Append('4'); break;
            case "0101": hexadecimal.Append('5'); break;
            case "0110": hexadecimal.Append('6'); break;
            case "0111": hexadecimal.Append('7'); break;
            case "1000": hexadecimal.Append('8'); break;
            case "1001": hexadecimal.Append('9'); break;
            case "1010": hexadecimal.Append('A'); break;
            case "1011": hexadecimal.Append('B'); break;
            case "1100": hexadecimal.Append('C'); break;
            case "1101": hexadecimal.Append('D'); break;
            case "1110": hexadecimal.Append('E'); break;
            case "1111": hexadecimal.Append('F'); break;
            default:
                return "Invalid number";
        }
    }

    if (isNegative)
    {
        hexadecimal.Insert(0, '-');
    }

    return hexadecimal.ToString();
}

Answer 3

If you're using .NET 4.0 or later and if you're willing to use System.Numerics.dll (for BigInteger class), the following solution works fine:

public static string ConvertBigBinaryToHex(string bigBinary)
{
    BigInteger bigInt = BigInteger.Zero;
    int exponent = 0;

    for (int i = bigBinary.Length - 1; i >= 0; i--, exponent++)
    {
        if (bigBinary[i] == '1')
            bigInt += BigInteger.Pow(2, exponent);
    }

    return bigInt.ToString("X");
}

Answer 4

Convert.ToInt32("1011", 2).ToString("X");

For string longer than this, you can simply break it into multiple bytes:

var binary = "0110011010010111001001110101011100110100001101101000011001010110001101101011";
var hex = string.Join(" ", 
            Enumerable.Range(0, binary.Length / 8)
            .Select(i => Convert.ToByte(binary.Substring(i * 8, 8), 2).ToString("X2")));