issue with comparing two numbers in javascript

Question

my html code is like:

Answer 1

When you compare two strings in an if statement:

if ( l > h) {}    
when l = "12" and h = "112"

It compares these two values as strings as "3" > "1". It says l > h is true

Answer 2

You need to convert them to numbers:

if(+l > +h){

The unary plus operator will convert the string value to numeric value. See this question for more details:
What's the significant use of unary plus and minus operators?

Live example.

Answer 3

try like this :-

if(parseInt(l,10)>parseInt(h,10))

or for floating Numbers you can use

if(parseFloat(l,10)>parseFloat(h,10))

or simply use

Number()

Answer 4

Use parseInt with base to get correct results:

var l = parseInt(document.test.low.value, 10);
var h = parseInt(document.test.high.value, 10);

Answer 5

var lnum = new Number(l);
var hnmu = new Number(h);
if(lnum > hnum){
alert('if');

}else{
alert('else');
}