org.json.JSONException: Value <br of type java.lang.String cannot be converted to JSONObject

Question

I m trying to do a registration page from an android activity connectiong the datas to my sqldatabase, I m getting this error \" org.json.JSONException: Value

First of

Answer 1

I have the same problem; i found the solution the easy way.

In Java code just type Log.e("anyText",response); In logCat it will show you what is problem

Answer 2

Thanks I manage to correct some of the errors 2 ';' were missing and I could see the error with Log.i("tagconvertstr", "["+result+"]");

The msg that it is showing is something like that :

[<br/ > font size = 1 table class=''xdebug-erroe' dir='ltr' ... loads of html code that wasn't in my initial code then....{"message":"Problem sending you the activation mail !"}]

So there's a problem with the json format on that message "Problem sending you the activation mail" but the user was registered OK!

So the second time i would try that code it would show me in a correct json format : "This email has already been used" ! (without any errors) but i still can't find the error in my php code : S

Answer 3

You should set Content-Type header before sending back the response.

header('Content-Type: application/json');
print(json_encode(array("message" => $msg)));

Check this : Returning JSON from a PHP Script

Answer 4

try preventing any output before your print and change the print to echo

you may also remove the closing ?> to prevent further output after the php script

<?php
ob_start();
if( isset($_POST['login']) && isset($_POST['pwd']) && isset($_POST['name']) && isset($_POST['firstname'])) {

    include("connexion_bdd.php");

    if(connexionBDD() == 1){

        $login = $_POST['login'];
        $pwd = $_POST['pwd'];
        $name = $_POST['name'];
        $firstname = $_POST['firstname'];

        $sql = "SELECT colUserID
                FROM userTable 
                WHERE colUserLogin = '".$login."' ";

        $req = mysql_query($sql);
        $resultat=mysql_num_rows($req); 

        if($resultat==0){
            $temps = time();
            $clef = md5($login . $temps);

            $req = mysql_query("INSERT INTO userTable(colUserLogin, colUserPwd, colUserName, colUserFirstname, colUserKey, colUserDate)
                                        VALUES( '$login', '$pwd', '$name', '$firstname', '$clef', '$temps')");

            if($req){
                    $destinataire = $login;
                    $sujet ="Welcome on SnSR";
                    $from = "From: SpotnShareReminder@live.com \r\n";
                    $from .= "Content-Type: text/html; charset=us-ascii\r\n";

                    $message = ' Clic on the link below :<br/>
                    <a href="http://localhost/spotnshare/validation_mail.php?usrk='.$clef.' ">
                        Registration confirmation.
                    </a> ';

                    ini_set('SMTP','relay.skynet.be');

                    if(mail($destinataire,$sujet,$message,$from)){
                        $msg = 'Check your mailbox to activate your account !'; 
                    }           
                    else{
                        $msg = 'Problem sending you the activation mail !'; 
                        $req = mysql_query("DELETE FROM userTable WHERE colUserLogin = '".$pseudo."' ");
                    }
            }
            else{
                $msg = 'Problem inserting you in our database !';
            }
        }else{
                $msg = 'This email has already been used !';
        }
        mysql_free_result ($req);   

    }else{
        $msg = "Connexion problem with de DB"
        print(json_encode(array("message" => $msg)));       
    }

}else{
        $msg = "Couldn't treat your datas"
}
ob_end_clean()
echo(json_encode(array("message" => $msg)));

Answer 5

Your request to http://192.168.1.101/spotnshare/subscribe.php is failing and returning a non-JSON string (probably a PHP error). You can print out the value with a

Log.i("tagconvertstr", "["+result+"]");

before the new JSONObject call to see what you're getting before parsing it.

EDIT: if you are using Eclipse you can set a break point and step through to see what's going on.