laravel 4 custom named password column

Question

So I found a few problems already which says that you have to override getAuthPassword() to give custom name of password column from database. Tried putting this method with

Answer 1

Here is my way of changing the default email field of the Laravel login to 'email_address' without changing the vendor code.

I made a trait class that extends the vendor AuthenticatesUsers trait. And only extended the username method.

App\Http\Controllers\Auth\AuthenticatesLogins.php:

namespace App\Http\Controllers\Auth;

use Illuminate\Foundation\Auth\AuthenticatesUsers;

trait AuthenticatesLogins
{
    use AuthenticatesUsers {
        AuthenticatesUsers::username as parentUsername;
    }

    /**
     * Get the login username to be used by the controller.
     *
     * @return string
     */
    public function username()
    {
        $this->parentUsername();
        return 'email_address';
    }
}

Now in App\Http\Controllers\Controller\LoginController.php:

class LoginController extends Controller
{
    use AuthenticatesLogins; // <-- for custom login fields
    // etc.

And... done! Hope this helps.

Answer 2

There's a static solution for situations when implementing the given interface is not enough (e.g. you have two password columns, a user password and a support password).

$qry = DB::table('users')
        ->where('email', $email)
        ->whereNotNull('support_password')
        ->first();

if(!empty($qry))
{
    $check = Hash::check($password, $qry->support_password);
    if ($check)
    {
        Auth::loginUsingId($qry->id, true);
    }
}

Answer 3

tldr; You can name your password field anything you like, as long as your User model implements the interface correctly.

However you can't pass different array key to the Auth::attempt method - only password index can be there

First off you're doing it wrong - you need to pass an array of credentials as 1st param:

if (Auth::attempt(Input::only('user_displayName', 'user_password')))

Next, unfortunately Eloquent provider has hard-coded password array index in the code, so you can't pass user_password to the attempt method.

So this is what you need:

$credentials = Input::only('user_displayName');
$credentials['password'] = Input::get('user_password');

if (Auth::attempt($credentials))

// or simply rename the input in your form to password and:
if (Auth::attempt(Input::only('user_displayName', 'password')))

Answer 4

I have not tested this but I believe you just have to override a function in UserTrait.php although don't hack the source. In your models/User.php file add the following function.

/**
 * Get the password for the user.
 *
 * @return string
 */
public function getAuthPassword()
{
    return $this->user_password;
}