While constructing the default constructor can not handle exception : type Exception thrown by implicit super constructor

Question

The code works fine until I try to make the code into a constructable class. When I attempt to construct an object from it I get the error

\"Default

Answer 1

Just enclose your call to the Constructor in a Try-Catch.

Answer 2

Default constructor implicitly invokes super constructor which is assumed to be throwing some exception which you need to handle in sub class's constructor . for detailed answer post the code

class Base{

  public Base() throw SomeException{
    //some code
  }

}

class Child extends Base{
  public Child(){
   //here it implicitly invokes `Base()`, So handle it here
  }
}

Answer 3

Any subclass which extends a super class whose default constructor handles some exception, a subclass must have a default constructor which implements the exception

class Super{ public Super() throws Exception {}}

class Sub extends Super{public Sub()throws Exception{//}}

Answer 4

Base class super.constructor is implicitly invoked by the extending class constructor:

class Base
{
  public Base () throws Exception
  {
    throw <>;
  }
}

class Derived extends Base
{
  public Derived ()
  {
  }
}

Now, one need to handle the exception inside Derived() or make the constructor as,

public Derived() throws Exception
{
}

Whatever method you new up the object of Derived, either you enclose it in try-catch or make that method throwing Exception as above. [Note: this is pseudo code]