Open multiple links in Chrome at once as new tabs

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I\'m trying to open multiple links at once in Google Chrome in new tabs but it fails.

Problems:

Blocked by popup
Open in new windows instead o

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7条回答

时光说笑

2020-11-29 09:43

Since modern browsers (and even old ones with blockers), will absolutely not allow this (one user action, one new tab). My solution was:

    openInfoLinks = () => {
        const urlsArray = [
            `https://...`,
            `https://...`,
            `https://...`,
        ]
        window.open(
            urlsArray[this.linkCounter],
            `_blank_${someIdentifier}_${this.linkCounter}`
        );
        this.linkCounter++;
        setTimeout(() => {
            this.linkCounter = 0;
        }, 500);
    }

The user can open the links in quick succession with ctrl+click-ing the button N times.

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小鲜肉

2020-11-29 09:50

The following code will open multiple popUp on the button click.

<html>
<head>
<title></title>
<script type="text/javascript">
  function open_win() {
 window.open("url","windowName","windowFeatures")
 window.open("url","DifferentWindowName","windowFeatures")// different name for each popup
}
</script>
</head>

<body>
<form>
<input type=button value="Open Windows" onclick="open_win()">
</form>
</body>

you need to make sure that each window name is different, otherwise the last popup will overwrite it's previous popup. As a result you will end up with a single popup.

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误落风尘

2020-11-29 09:51

The best way to open multiple tabs or windows is by using setTimeout() of 500ms.

window.open("https://facebook.com", "one", windowFeatures);
setTimeout(function(){
  window.open("https://facebook.com", "two", windowFeatures);
}, 500);

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天命终不由人

2020-11-29 09:52

Looks like extension uses below code to open those tabs.

function openTab(urls, delay, window_id, tab_position, close_time) {
    var obj = {
            windowId: window_id,
            url: urls.shift().url,
            selected: false
    }

    if(tab_position != null) {
        obj.index = tab_position
        tab_position++;
    }

    chrome.tabs.create(obj, function(tab) {
        if(close_time > 0) {
            window.setTimeout(function() {
                chrome.tabs.remove(tab.id);
            }, close_time*1000);
        }
    });

    if(urls.length > 0) {
        window.setTimeout(function() {openTab(urls, delay, window_id, tab_position, close_time)}, delay*1000);
    }

}

If you want to take a look at the code of the extension for reference you will find the extensions in (for Windows) C:\Documents and Settings\*UserName*\Local Settings\Application Data\Google\Chrome\User Data\Default\Extensions

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遇见更好的自我

2020-11-29 10:09

You can do this in vanilla JavaScript:

<html>
<head>
<script type="text/javascript">
function open_win() {
    window.open("http://www.java2s.com/")
    window.open("http://www.java2s.com/")
}
</script>
</head>

<body>
<form>
<input type=button value="Open Windows" onclick="open_win()">
</form>
</body>

</html>

Here is a more Chrome-specific implementation (if popup blockers are giving you difficulty):

var linkArray = []; // your links
for (var i = 0; i < linkArray.length; i++) {
    // will open each link in the current window
    chrome.tabs.create({
        url: linkArray[i]
    });
}

Here is some documentation: https://developer.chrome.com/extensions/tabs

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暗喜

2020-11-29 10:09
The reason that the browser extension can do it is because Chrome extensions have access to a special Chrome API, which lets you use:
```
chrome.windows.create({tabid: n})
```
where createData has a tabid value greater than any current tab (and you can find the greatest current tabid using chrome.windows.getAll()).

However, in terms of doing it on your page (or anywhere that's not a Chrome extension), that's not possible, since whether or not a new window opens in a new tab is determined entirely by the user's settings.
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