Extract `src` attribute from `img` tag using BeautifulSoup

Question

I use bs4 an

Answer 1

You can use BeautifulSoup to extract src attribute of an html img tag. In my example, the htmlText contains the img tag itself but this can be used for a URL too along with urllib2.

The solution provided by the most rated answer is not working any more with python3. This is the correct implementation:

For URLs

from bs4 import BeautifulSoup as BSHTML
import urllib3

http = urllib3.PoolManager()
url = 'your_url'

response = http.request('GET', url)
soup = BSHTML(response.data, "html.parser")
images = soup.findAll('img')

for image in images:
    #print image source
    print(image['src'])
    #print alternate text
    print(image['alt'])

For Texts with img tag

from bs4 import BeautifulSoup as BSHTML
htmlText = """<img src="https://src1.com/" <img src="https://src2.com/" /> """
soup = BSHTML(htmlText)
images = soup.findAll('img')
for image in images:
    print(image['src'])

Answer 2

here is a solution that will not trigger a KeyError in case the img tag does not have a src attribute:

from urllib.request import urlopen
from bs4 import BeautifulSoup

site = "[insert name of the site]"
html = urlopen(site)
bs = BeautifulSoup(html, 'html.parser')

images = bs.find_all('img')
for img in images:
    if img.has_attr('src'):
        print(img['src'])

Answer 3

A link doesn't have attribute src you have to target actual img tag.

import bs4

html = """<div class="someClass">
    <a href="href">
        <img alt="some" src="some"/>
    </a>
</div>"""

soup = bs4.BeautifulSoup(html, "html.parser")

# this will return src attrib from img tag that is inside 'a' tag
soup.a.img['src']

>>> 'some'

# if you have more then one 'a' tag
for a in soup.find_all('a'):
    if a.img:
        print(a.img['src'])

>>> 'some'

Answer 4

You can use BeautifulSoup to extract src attribute of an html img tag. In my example, the htmlText contains the img tag itself but this can be used for a URL too along with urllib2.

For URLs

from BeautifulSoup import BeautifulSoup as BSHTML
import urllib2
page = urllib2.urlopen('http://www.youtube.com/')
soup = BSHTML(page)
images = soup.findAll('img')
for image in images:
    #print image source
    print image['src']
    #print alternate text
    print image['alt']

For Texts with img tag

from BeautifulSoup import BeautifulSoup as BSHTML
htmlText = """<img src="https://src1.com/" <img src="https://src2.com/" /> """
soup = BSHTML(htmlText)
images = soup.findAll('img')
for image in images:
    print image['src']