Python Dictionary Comprehension

Question

Is it possible to create a dictionary comprehension in Python (for the keys)?

Without list comprehensions, you can use something like this:

l = []
fo         


        

Answer 1

Use dict() on a list of tuples, this solution will allow you to have arbitrary values in each list, so long as they are the same length

i_s = range(1, 11)
x_s = range(1, 11)
# x_s = range(11, 1, -1) # Also works
d = dict([(i_s[index], x_s[index], ) for index in range(len(i_s))])

Answer 2

The main purpose of a list comprehension is to create a new list based on another one without changing or destroying the original list.

Instead of writing

l = []
for n in range(1, 11):
    l.append(n)

or

l = [n for n in range(1, 11)]

you should write only

l = range(1, 11)

In the two top code blocks you're creating a new list, iterating through it and just returning each element. It's just an expensive way of creating a list copy.

To get a new dictionary with all keys set to the same value based on another dict, do this:

old_dict = {'a': 1, 'c': 3, 'b': 2}
new_dict = { key:'your value here' for key in old_dict.keys()}

You're receiving a SyntaxError because when you write

d = {}
d[i for i in range(1, 11)] = True

you're basically saying: "Set my key 'i for i in range(1, 11)' to True" and "i for i in range(1, 11)" is not a valid key, it's just a syntax error. If dicts supported lists as keys, you would do something like

d[[i for i in range(1, 11)]] = True

and not

d[i for i in range(1, 11)] = True

but lists are not hashable, so you can't use them as dict keys.