Get escaped URL parameter

Question

I\'m looking for a jQuery plugin that can get URL parameters, and support this search string without outputting the JavaScript error: \"malformed URI sequence\". If there is

Answer 1

function getURLParameters(paramName) 
{
        var sURL = window.document.URL.toString();  
    if (sURL.indexOf("?") > 0)
    {
       var arrParams = sURL.split("?");         
       var arrURLParams = arrParams[1].split("&");      
       var arrParamNames = new Array(arrURLParams.length);
       var arrParamValues = new Array(arrURLParams.length);     
       var i = 0;
       for (i=0;i<arrURLParams.length;i++)
       {
        var sParam =  arrURLParams[i].split("=");
        arrParamNames[i] = sParam[0];
        if (sParam[1] != "")
            arrParamValues[i] = unescape(sParam[1]);
        else
            arrParamValues[i] = "No Value";
       }

       for (i=0;i<arrURLParams.length;i++)
       {
                if(arrParamNames[i] == paramName){
            //alert("Param:"+arrParamValues[i]);
                return arrParamValues[i];
             }
       }
       return "No Parameters Found";
    }

}

Answer 2

If you don't know what the URL parameters will be and want to get an object with the keys and values that are in the parameters, you can use this:

function getParameters() {
  var searchString = window.location.search.substring(1),
      params = searchString.split("&"),
      hash = {};

  if (searchString == "") return {};
  for (var i = 0; i < params.length; i++) {
    var val = params[i].split("=");
    hash[unescape(val[0])] = unescape(val[1]);
  }
  return hash;
}

Calling getParameters() with a url like /posts?date=9/10/11&author=nilbus would return:

{
  date:   '9/10/11',
  author: 'nilbus'
}

I won't include the code here since it's even farther away from the question, but weareon.net posted a library that allows manipulation of the parameters in the URL too:

• Blog post: http://blog.weareon.net/working-with-url-parameters-in-javascript/
• Code: http://pastebin.ubuntu.com/1163515/

Answer 3

I created a simple function to get URL parameter in JavaScript from a URL like this:

.....58e/web/viewer.html?page=*17*&getinfo=33


function buildLinkb(param) {
    var val = document.URL;
    var url = val.substr(val.indexOf(param))  
    var n=parseInt(url.replace(param+"=",""));
    alert(n+1); 
}
buildLinkb("page");

OUTPUT: 18

Answer 4

You can use the browser native location.search property:

function getParameter(paramName) {
  var searchString = window.location.search.substring(1),
      i, val, params = searchString.split("&");

  for (i=0;i<params.length;i++) {
    val = params[i].split("=");
    if (val[0] == paramName) {
      return unescape(val[1]);
    }
  }
  return null;
}

But there are some jQuery plugins that can help you:

• query-object
• getURLParam

Answer 5

Slight modification to the answer by @pauloppenheim , as it will not properly handle parameter names which can be a part of other parameter names.

Eg: If you have "appenv" & "env" parameters, redeaing the value for "env" can pick-up "appenv" value.

Fix:

var urlParamVal = function (name) {
    var result = RegExp("(&|\\?)" + name + "=(.+?)(&|$)").exec(location.search);
    return result ? decodeURIComponent(result[2]) : "";
};

Answer 6

Based on the 999's answer:

function getURLParameter(name) {
    return decodeURIComponent(
        (location.search.match(RegExp("[?|&]"+name+'=(.+?)(&|$)'))||[,null])[1]
    );  
}

Changes:

• decodeURI() is replaced with decodeURIComponent()
• [?|&] is added at the beginning of the regexp