Python - Round to nearest 05

Question

Hvor can I en python do the following rounding:

Round to the nearest 05 decimal

7,97 -> 7,95

6,72 -> 6,70

31,06 -> 31,05

36,04 -> 36,

Answer 1

Using lambda function:

>>> nearest_half = lambda x: round(x * 2) / 2
>>> nearest_half(5.2)
5.0
>>> nearest_half(5.25)
5.5
>>> nearest_half(5.26)
5.5
>>> nearest_half(5.5)
5.5
>>> nearest_half(5.75)
6.0

Answer 2

To round it to exactly how you want to:

>>> def foo(x, base=0.05):
...     return round(base*round(x/base), 2)

>>> foo(5.75)
5.75
>>> foo(5.775)
5.8
>>> foo(5.77)
5.75
>>> foo(7.97)
7.95
>>> foo(6.72)
6.7
>>> foo(31.06)
31.05
>>> foo(36.04)
36.05
>>> foo(5.25)
5.25

Answer 3

import numpy as np

for Roundup

df['a']=(df["a"]*2).apply(np.ceil)/2

for Round

df['a']=(df["a"]*2).apply(np.floor)/2

This is working with columns for roundup 0.5 using numpy...