GetType()
is a method of object
.
To call it, the Nullable<T>
struct must be boxed.
You can see this in the IL code:
//int? x = 5;
IL_0000: ldloca.s 00
IL_0002: ldc.i4.5
IL_0003: call System.Nullable<System.Int32>..ctor
//Console.WriteLine(x.GetType());
IL_0008: ldloc.0
IL_0009: box System.Nullable<System.Int32>
IL_000E: callvirt System.Object.GetType
IL_0013: call System.Console.WriteLine
Nullable types are treated specially by CLR; it is impossible to have a boxed instance of a nullable type.
Instead, boxing a nullable type will result in a null reference (if HasValue
is false), or the boxed value (if there is a value).
Therefore, the box System.Nullable<System.Int32>
instruction results in a boxed Int32
, not a boxed Nullable<Int32>
.
Therefore, it is impossible for GetType()
to ever return Nullable<T>
.
To see this more clearly, look at the following code:
static void Main()
{
int? x = 5;
PrintType(x);
}
static void PrintType<T>(T val) {
Console.WriteLine("Compile-time type: " + typeof(T));
Console.WriteLine("Run-time type: " + val.GetType());
}
This prints
Compile-time type: System.Nullable`1[System.Int32]
Run-time type: System.Int32