Does R have function startswith or endswith like python? [closed]

Answer 1

The simplest way I can think of is to use the %like% operator:

library(data.table)

"foo" %like% "^f" 

evaluates as TRUE - Starting with f

"foo" %like% "o$" 

evaluates as TRUE - Ending with o

"bar" %like% "a"

evaluates as TRUE - Containing a

Answer 2

This is relatively simple by using the substring function:

> strings = c("abc", "bcd", "def", "ghi", "xyzzd", "a")
> str_to_find = "de"
> substring(strings, 1, nchar(str_to_find)) == str_to_find
[1] FALSE FALSE  TRUE FALSE FALSE FALSE

You cut each string to the desired length with substring. The length being the number of characters you are looking for at the beginning of each string.

Answer 3

Not inbuilt like that.

Options include grepl and substr.

x <- 'ABCDE'
grepl('^AB', x) # starts with AB?
grepl('DE$', x) # ends with DE?
substr(x, 1, 2) == 'AB'
substr('ABCDE', nchar(x)-1, nchar(x)) == 'DE'

Answer 4

The dplyr package's select statement supports starts_with and ends_with. For example, this selects the columns of the iris data frame that start with Petal

library(dplyr)
select(iris, starts_with("Petal"))

select supports other subcommands too. Try ?select .

Answer 5

As added to base in 3.3.0, startsWith (and endsWith) are exactly this.

> startsWith("what", "wha")
[1] TRUE
> startsWith("what", "ha")
[1] FALSE

https://stat.ethz.ch/R-manual/R-devel/library/base/html/startsWith.html

Answer 6

Borrowing some code from the dplyr package [see this] you could do something like this:

starts_with <- function(vars, match, ignore.case = TRUE) {
  if (ignore.case) match <- tolower(match)
  n <- nchar(match)

  if (ignore.case) vars <- tolower(vars)
  substr(vars, 1, n) == match
}

ends_with <- function(vars, match, ignore.case = TRUE) {
  if (ignore.case) match <- tolower(match)
  n <- nchar(match)

  if (ignore.case) vars <- tolower(vars)
  length <- nchar(vars)

  substr(vars, pmax(1, length - n + 1), length) == match
}