XPath to return string concatenation of qualifying child node values

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太阳男子
太阳男子 2020-11-29 07:44

Can anyone please suggest an XPath expression format that returns a string value containing the concatenated values of certain qualifying child nodes of an element, but igno

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  • 2020-11-29 07:53

    If you want all children except p, you can try the following...

        string-join(//*[name() != 'p']/text(), "")
    

    which returns...

    This text node should be returned.
    And the value of this element.
    And this.
    
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  • 2020-11-29 07:53

    You could use a for-each loop as well and assemble the values in a variable like this

    <xsl:variable name="newstring">
        <xsl:for-each select="/div//text()">
          <xsl:value-of select="."/>
        </xsl:for-each>
      </xsl:variable>
    
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  • 2020-11-29 07:54

    In XPath 1.0:

    You can use

    /div//text()[not(parent::p)]
    

    to capture the wanted text nodes. The concatenation itself cannot be done in XPath 1.0, I recommend doing it in the host application.

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  • 2020-11-29 07:58
    /div//text()
    

    double slash forces to extract text regardless of intermediate nodes

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  • 2020-11-29 08:03

    In XPath 2.0 :

    string-join(/*/node()[not(self::p)], '')

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  • 2020-11-29 08:13

    I know this comes a bit late, but I figure my answer could still be relevant. I recently ran into a similar problem. And because I use scrapy in Python 3.6, which does not support xpath 2.0, I could not use the string-join function suggested in several online answers.

    I ended up finding a simple workaround (as shown below) which I did not see in any of the stackoverflow answers, that's why I'm sharing it.

    temp_selector_list = response.xpath('/div')
    string_result = [''.join(x.xpath(".//text()").extract()) for x in temp_selector_list]
    

    Hope this helps!

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