Pass Model To Controller using Jquery/Ajax

Question

I am trying to pass my model to a controller using JQuery/Ajax, I\'m not sure how to do this correctly. So far I have tried using Url.Action but the model is

Answer 1

//C# class

public class DashBoardViewModel 
{
    public int Id { get; set;} 
    public decimal TotalSales { get; set;} 
    public string Url { get; set;} 
     public string MyDate{ get; set;} 
}

//JavaScript file
//Create dashboard.js file
$(document).ready(function () {

    // See the html on the View below
    $('.dashboardUrl').on('click', function(){
        var url = $(this).attr("href"); 
    });

    $("#inpDateCompleted").change(function () {   

        // Construct your view model to send to the controller
        // Pass viewModel to ajax function 

        // Date
        var myDate = $('.myDate').val();

        // IF YOU USE @Html.EditorFor(), the myDate is as below
        var myDate = $('#MyDate').val();
        var viewModel = { Id : 1, TotalSales: 50, Url: url, MyDate: myDate };


        $.ajax({
            type: 'GET',
            dataType: 'json',
            cache: false,
            url: '/Dashboard/IndexPartial',
            data: viewModel ,
            success: function (data, textStatus, jqXHR) {
                //Do Stuff 
                $("#DailyInvoiceItems").html(data.Id);
            },
            error: function (jqXHR, textStatus, errorThrown) {
                //Do Stuff or Nothing
            }
        });

    });
});

//ASP.NET 5 MVC 6 Controller
public class DashboardController {

    [HttpGet]
    public IActionResult IndexPartial(DashBoardViewModel viewModel )
    {
        // Do stuff with my model
        var model = new DashBoardViewModel {  Id = 23 /* Some more results here*/ };
        return Json(model);
    }
}

// MVC View 
// Include jQuerylibrary
// Include dashboard.js 
<script src="~/Scripts/jquery-2.1.3.js"></script>
<script src="~/Scripts/dashboard.js"></script>
// If you want to capture your URL dynamically 

<div>
    <a class="dashboardUrl" href ="@Url.Action("IndexPartial","Dashboard")"> LinkText </a>
</div>
<div>
    <input class="myDate" type="text"/>
//OR
   @Html.EditorFor(model => model.MyDate) 
</div>

Answer 2

As suggested in other answers it's probably easiest to "POST" the form data to the controller. If you need to pass an entire Model/Form you can easily do this with serialize() e.g.

$('#myform').on('submit', function(e){
    e.preventDefault();

    var formData = $(this).serialize();

    $.post('/student/update', formData, function(response){
         //Do something with response
    });
});

So your controller could have a view model as the param e.g.

 [HttpPost]
 public JsonResult Update(StudentViewModel studentViewModel)
 {}

Alternatively if you just want to post some specific values you can do:

$('#myform').on('submit', function(e){
    e.preventDefault();

    var studentId = $(this).find('#Student_StudentId');
    var isActive = $(this).find('#Student_IsActive');

    $.post('/my/url', {studentId : studentId, isActive : isActive}, function(response){
         //Do something with response
    });
});

With a controller like:

     [HttpPost]
     public JsonResult Update(int studentId, bool isActive)
     {}

Answer 3

Looks like your IndexPartial action method has an argument which is a complex object. If you are passing a a lot of data (complex object), It might be a good idea to convert your action method to a HttpPost action method and use jQuery post to post data to that. GET has limitation on the query string value.

[HttpPost]
public PartialViewResult IndexPartial(DashboardViewModel m)
{
   //May be you want to pass the posted model to the parial view?
   return PartialView("_IndexPartial");
}

Your script should be

var url = "@Url.Action("IndexPartial","YourControllerName")";

var model = { Name :"Shyju", Location:"Detroit"};

$.post(url, model, function(res){
   //res contains the markup returned by the partial view
   //You probably want to set that to some Div.
   $("#SomeDivToShowTheResult").html(res);
});

Assuming Name and Location are properties of your DashboardViewModel class and SomeDivToShowTheResult is the id of a div in your page where you want to load the content coming from the partialview.

Sending complex objects?

You can build more complex object in js if you want. Model binding will work as long as your structure matches with the viewmodel class

var model = { Name :"Shyju", 
              Location:"Detroit", 
              Interests : ["Code","Coffee","Stackoverflow"]
            };

$.ajax({
    type: "POST",
    data: JSON.stringify(model),
    url: url,
    contentType: "application/json"
}).done(function (res) {
    $("#SomeDivToShowTheResult").html(res);
});

For the above js model to be transformed to your method parameter, Your View Model should be like this.

public class DashboardViewModel
{
  public string Name {set;get;}
  public string Location {set;get;}
  public List<string> Interests {set;get;}
}

And in your action method, specify [FromBody]

[HttpPost]
public PartialViewResult IndexPartial([FromBody] DashboardViewModel m)
{
    return PartialView("_IndexPartial",m);
}

Answer 4

Use the following JS:

$(document).ready(function () {
    $("#btnsubmit").click(function () {

             $.ajax({
                 type: "POST",
                 url: '/Plan/PlanManage',     //your action
                 data: $('#PlanForm').serialize(),   //your form name.it takes all the values of model               
                 dataType: 'json',
                 success: function (result) {
                     console.log(result);
                 }
             })
        return false;
    });
});

and the following code on your controller:

[HttpPost]
public string PlanManage(Plan objplan)  //model plan
{
}