I am trying to get every single color of every single pixel of an image. My idea was following:
int[] pixels;
BufferedImage image;
image = ImageIO.read(this
I know this has already been answered, but the answers given are a bit convoluted and could use improvement. The simple idea is to just loop through every (x,y) pixel in the image, and get the color of that pixel.
BufferedImage image = MyImageLoader.getSomeImage();
for ( int x = 0; x < image.getWidth(); x++ ) {
for( int y = 0; y < image.getHeight(); y++ ) {
Color pixel = new Color( image.getRGB( x, y ) );
// Do something with pixel color here :)
}
}
You could then perhaps wrap this method in a class, and implement Java's Iterable API.
class IterableImage implements Iterable<Color> {
private BufferedImage image;
public IterableImage( BufferedImage image ) {
this.image = image;
}
@Override
public Iterator<Color> iterator() {
return new Itr();
}
private final class Itr implements Iterator<Color> {
private int x = 0, y = 0;
@Override
public boolean hasNext() {
return x < image.getWidth && y < image.getHeight();
}
@Override
public Color next() {
x += 1;
if ( x >= image.getWidth() ) {
x = 0;
y += 1;
}
return new Color( image.getRGB( x, y ) );
}
}
}
The usage of which might look something like the following
BufferedImage image = MyImageLoader.getSomeImage();
for ( Color color : new IterableImage( image ) ) {
// Do something with color here :)
}
import java.awt.Color;
import java.awt.image.BufferedImage;
import java.io.File;
import java.io.IOException;
import javax.imageio.ImageIO;
public class ImageUtil {
public static Color[][] loadPixelsFromImage(File file) throws IOException {
BufferedImage image = ImageIO.read(file);
Color[][] colors = new Color[image.getWidth()][image.getHeight()];
for (int x = 0; x < image.getWidth(); x++) {
for (int y = 0; y < image.getHeight(); y++) {
colors[x][y] = new Color(image.getRGB(x, y));
}
}
return colors;
}
public static void main(String[] args) throws IOException {
Color[][] colors = loadPixelsFromImage(new File("image.png"));
System.out.println("Color[0][0] = " + colors[0][0]);
}
}
The problem (also with the answer that was linked from the first answer) is that you hardly ever know what exact type your buffered image will be after reading it with ImageIO. It could contain a DataBufferByte
or a DataBufferInt
. You may deduce it in some cases via BufferedImage#getType()
, but in the worst case, it has type TYPE_CUSTOM
, and then you can only fall back to some instanceof
tests.
However, you can convert your image into a BufferedImage that is guaranteed to have a DataBufferInt
with ARGB values - namely with something like
public static BufferedImage convertToARGB(BufferedImage image)
{
BufferedImage newImage = new BufferedImage(
image.getWidth(), image.getHeight(),
BufferedImage.TYPE_INT_ARGB);
Graphics2D g = newImage.createGraphics();
g.drawImage(image, 0, 0, null);
g.dispose();
return newImage;
}
Otherwise, you can call image.getRGB(x,y)
, which may perform the required conversions on the fly.
BTW: Note that obtaining the data buffer of a BufferedImage may degrade painting performance, because the image can no longer be "managed" and kept in VRAM internally.
import java.io.*;
import java.awt.*;
import javax.imageio.ImageIO;
import java.awt.image.BufferedImage;
public class GetPixelColor {
public static void main(String args[]) throws IOException {
File file = new File("your_file.jpg");
BufferedImage image = ImageIO.read(file);
// Getting pixel color by position x and y
int clr = image.getRGB(x, y);
int red = (clr & 0x00ff0000) >> 16;
int green = (clr & 0x0000ff00) >> 8;
int blue = clr & 0x000000ff;
System.out.println("Red Color value = " + red);
System.out.println("Green Color value = " + green);
System.out.println("Blue Color value = " + blue);
}
}
of course you have to add a for loop for all pixels
import javax.imageio.ImageIO;
import java.awt.image.BufferedImage;
import java.io.File;
import java.io.IOException;
public class Main {
public static void main(String[] args) throws IOException {
BufferedImage bufferedImage = ImageIO.read(new File("norris.jpg"));
int height = bufferedImage.getHeight(), width = bufferedImage.getWidth();
for (int y = 0; y < height; y++) {
for (int x = 0; x < width; x++) {
int RGBA = bufferedImage.getRGB(x, y);
int alpha = (RGBA >> 24) & 255;
int red = (RGBA >> 16) & 255;
int green = (RGBA >> 8) & 255;
int blue = RGBA & 255;
}
}
}
}
Assume the buffered image represents an image with 8-bit RGBA color components packed into integer pixels, I search for "RGBA color space" on wikipedia and found following:
In the byte-order scheme, "RGBA" is understood to mean a byte R, followed by a byte G, followed by a byte B, and followed by a byte A. This scheme is commonly used for describing file formats or network protocols, which are both byte-oriented.
With simple Bitwise and Bitshift you can get the value of each color and the alpha value of the pixel.
Very interesting is also the other order scheme of RGBA:
In the word-order scheme, "RGBA" is understood to represent a complete 32-bit word, where R is more significant than G, which is more significant than B, which is more significant than A. This scheme can be used to describe the memory layout on a particular system. Its meaning varies depending on the endianness of the system.
byte[] pixels
not
int[] pixels
try this : Java - get pixel array from image