How to use php array with sql IN operator?

Question

I have and array with two values and I want to use it with sql IN operator in select query.

Here is the structure of my table

id comp_id
1   2
2   3
         


        

Answer 1

you need to convert the array into comma-separated string:

$condition = implode(', ', $arr);

And, additionally, you might want to escape the values first (if you are unsure about the input):

$condition = implode(', ', array_map('mysql_real_escape_string', $arr));

Answer 2

All the people here are proposing the same thing but i got a warning in WordPress because of a simple error. You need to add commas to your imploded string. To be precise something like this.

$query = "SELECT *FROM table Where comp_id IN ( '" . implode( "', '", $sanitized_brands ) . "' )";

Hoping it helps someone like me. :)

Answer 3

You're mixing PHP and SQL - for the IN SQL operator, you need a format like:

SELECT * from table WHERE comp_id IN (1,2)

So to get that in PHP you need to do something like:

$sql = "SELECT * from table Where comp_id IN (".implode(',',$arr).")"

Bear in mind that this only works if the array comprises of integers. You have to escape each element if they are strings.

Answer 4

You need something like:

$sql = "SELECT * from table where comp_id in (".implode(',',$arr.")";

Answer 5

you can only pass string to mysql as query, so try this

mysql_query("SELECT * FROM table WHERE comp_id IN (".implode(',',$arr).")");

Answer 6

If your array is of Integers :

$searchStringVar = implode(",",$nameIntAryVar);
$query="SELECT * from table NameTbl WHERE idCol='$idVar' AND comp_id IN ($searchStringVar)";

If your array is of Strings :

$searchStringVar = implode("','",$nameStringAryVar);
$query="SELECT * from table NameTbl WHERE idCol='$idVar' AND comp_id IN ('$searchStringVar')";