In my app, I have a requirement to format 12 hours
time to 24 hours
time. What is the method I have to use?
For example, time like 10
Try this:
import java.text.SimpleDateFormat;
import java.util.Date;
public class Main {
public static void main(String [] args) throws Exception {
SimpleDateFormat displayFormat = new SimpleDateFormat("HH:mm");
SimpleDateFormat parseFormat = new SimpleDateFormat("hh:mm a");
Date date = parseFormat.parse("10:30 PM");
System.out.println(parseFormat.format(date) + " = " + displayFormat.format(date));
}
}
which produces:
10:30 PM = 22:30
See: http://download.oracle.com/javase/1.5.0/docs/api/java/text/SimpleDateFormat.html
Try This
public static String convertTo24Hour(String Time) {
DateFormat f1 = new SimpleDateFormat("hh:mm a"); //11:00 pm
Date d = null;
try {
d = f1.parse(Time);
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
DateFormat f2 = new SimpleDateFormat("HH:mm");
String x = f2.format(d); // "23:00"
return x;
}
static String timeConversion(String s)
{
String s1[]=s.split(":");
char c[]=s1[2].toCharArray();
if(s1[2].contains("PM"))
{
int n=Integer.parseInt(s1[0]);
n=n+12;
return n+":"+s1[1]+":"+c[0]+c[1];
}
else``
return s1[0]+":"+s1[1]+":"+c[0]+c[1];
}
import java.text.SimpleDateFormat;
import java.text.DateFormat;
import java.util.Date;
public class Main {
public static void main(String [] args){
try {
DateFormat parseFormat = new SimpleDateFormat("dd-MM-yyyy hh:mm:ss a");
String sDate = "22-01-2019 9:0:0 PM";
Date date = parseFormat.parse(sDate);
SimpleDateFormat displayFormat = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
sDate = displayFormat.format(date);
LOGGER.info("The required format : " + sDate);
} catch (Exception e) {}
}
}
In Java 8 and later it could be done in one line using class java.time.LocalTime.
In the formatting pattern, lowercase hh
means 12-hour clock while uppercase HH
means 24-hour clock.
Code example:
String result = // Text representing the value of our date-time object.
LocalTime.parse( // Class representing a time-of-day value without a date and without a time zone.
"03:30 PM" , // Your `String` input text.
DateTimeFormatter.ofPattern( // Define a formatting pattern to match your input text.
"hh:mm a" ,
Locale.US // `Locale` determines the human language and cultural norms used in localization. Needed here to translate the `AM` & `PM` value.
) // Returns a `DateTimeFormatter` object.
) // Return a `LocalTime` object.
.format( DateTimeFormatter.ofPattern("HH:mm") ) // Generate text in a specific format. Returns a `String` object.
;
See this code run live at IdeOne.com.
15:30
See Oracle Tutorial.
first it will convert 12 hours time into 24 hours then it will take diff between two times
String a = "09/06/18 01:55:33 AM";
String b = "07/06/18 05:45:33 PM";
String [] b2 = b.split(" ");
String [] a2 = a.split(" ");
SimpleDateFormat displayFormat = new SimpleDateFormat("HH:mm:ss");
SimpleDateFormat parseFormat = new SimpleDateFormat("hh:mm:ss a");
String time1 = null ;
String time2 = null ;
if ( a.contains("PM") && b.contains("AM")) {
Date date = parseFormat.parse(a2[1]+" PM");
time1 = displayFormat.format(date);
time2 = b2[1];
}else if (b.contains("PM") && a.contains("AM")) {
Date date = parseFormat.parse(a2[1]+" PM");
time1 = a2[1];
time2 = displayFormat.format(date);
}else if (a.contains("PM") && b.contains("PM")){
Date datea = parseFormat.parse(a2[1]+" PM");
Date dateb = parseFormat.parse(b2[1]+" PM");
time1 = displayFormat.format(datea);
time2 = displayFormat.format(dateb);
}
System.out.println(time1);
System.out.println(time2);
SimpleDateFormat format = new SimpleDateFormat("HH:mm:ss");
Date date1 = format.parse(time1);
Date date2 = format.parse(time2);
long difference = date2.getTime() - date1.getTime();
System.out.println(difference);
System.out.println("Duration: "+DurationFormatUtils.formatDuration(difference, "HH:mm"));
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