My argparse has only 3 flags (store_true) on the top level, everything else is handled through subparsers. When I run myprog.py --help
, the output shows a list
A simpler way to iterate over the subparsers in Adaephon's example is
for subparser in [parser_a, parser_b]:
subparser.format_help()
Python does allow you to access hidden attributes like parser._actions
, but that's not encouraged. It is just as easy to build your own list while defining the parser. Same goes for doing special things with the arguments. add_argument
and add_subparser
return their respective Action
and Parser
objects for a reason.
If I were making a subclass of ArgumentParser
I would feel free to use _actions
. But for a one off application, building my own list would be clearer.
An example:
import argparse
parser = argparse.ArgumentParser()
parser.add_argument('mainpos')
parser.add_argument('--mainopt')
sp = parser.add_subparsers()
splist = [] # list to collect subparsers
sp1 = sp.add_parser('cmd1')
splist.append(sp1)
sp1.add_argument('--sp1opt')
sp2 = sp.add_parser('cmd2')
splist.append(sp2)
sp2.add_argument('--sp2opt')
# collect and display for helps
helps = []
helps.append(parser.format_help())
for p in splist:
helps.append(p.format_help())
print('\n'.join(helps))
# or to show just the usage
helps = []
helps.append(parser.format_usage())
for p in splist:
helps.append(p.format_usage())
print(''.join(helps))
The combined 'usage' display is:
usage: stack32607706.py [-h] [--mainopt MAINOPT] mainpos {cmd1,cmd2} ...
usage: stack32607706.py mainpos cmd1 [-h] [--sp1opt SP1OPT]
usage: stack32607706.py mainpos cmd2 [-h] [--sp2opt SP2OPT]
The display of the combined helps is long and redundant. It could be edited in various ways, either after formatting, or with special help formatters. But who is going make such choices?
Perhaps an easier approach is to use parser.epilog
:
def define_parser():
import argparse
parser = argparse.ArgumentParser(
prog='main',
formatter_class=argparse.RawDescriptionHelpFormatter,
)
commands = parser.add_subparsers(
title="required commands",
help='Select one of:',
)
command_list = commands.add_parser(
'list',
help='List included services',
)
command_ensure = commands.add_parser(
'ensure',
help='Provision included service',
)
command_ensure.add_argument(
"service",
help='Service name',
)
import textwrap
parser.epilog = textwrap.dedent(
f"""\
commands usage:\n
{command_list.format_usage()}
{command_ensure.format_usage()}
"""
)
return parser
parser = define_parser()
parser.print_help()
which results in the following output:
usage: main [-h] {list,ensure} ...
optional arguments:
-h, --help show this help message and exit
required commands:
{list,ensure} Select one of:
list List included services
ensure Provision included service
commands usage:
usage: main list [-h]
usage: main ensure [-h] service
This is a bit tricky, as argparse does not expose a list of defined sub-parsers directly. But it can be done:
import argparse
# create the top-level parser
parser = argparse.ArgumentParser(prog='PROG')
parser.add_argument('--foo', action='store_true', help='foo help')
subparsers = parser.add_subparsers(help='sub-command help')
# create the parser for the "a" command
parser_a = subparsers.add_parser('a', help='a help')
parser_a.add_argument('bar', type=int, help='bar help')
# create the parser for the "b" command
parser_b = subparsers.add_parser('b', help='b help')
parser_b.add_argument('--baz', choices='XYZ', help='baz help')
# print main help
print(parser.format_help())
# retrieve subparsers from parser
subparsers_actions = [
action for action in parser._actions
if isinstance(action, argparse._SubParsersAction)]
# there will probably only be one subparser_action,
# but better safe than sorry
for subparsers_action in subparsers_actions:
# get all subparsers and print help
for choice, subparser in subparsers_action.choices.items():
print("Subparser '{}'".format(choice))
print(subparser.format_help())
This example should work for python 2.7 and python 3. The example parser is from Python 2.7 documentation on argparse sub-commands.
The only thing left to do is adding a new argument for the complete help, or replacing the built in -h/--help
.
Here is complete soulution with custom help handler (almost all code from @Adaephon answer):
import argparse
class _HelpAction(argparse._HelpAction):
def __call__(self, parser, namespace, values, option_string=None):
parser.print_help()
# retrieve subparsers from parser
subparsers_actions = [
action for action in parser._actions
if isinstance(action, argparse._SubParsersAction)]
# there will probably only be one subparser_action,
# but better save than sorry
for subparsers_action in subparsers_actions:
# get all subparsers and print help
for choice, subparser in subparsers_action.choices.items():
print("Subparser '{}'".format(choice))
print(subparser.format_help())
parser.exit()
# create the top-level parser
parser = argparse.ArgumentParser(prog='PROG', add_help=False) # here we turn off default help action
parser.add_argument('--help', action=_HelpAction, help='help for help if you need some help') # add custom help
parser.add_argument('--foo', action='store_true', help='foo help')
subparsers = parser.add_subparsers(help='sub-command help')
# create the parser for the "a" command
parser_a = subparsers.add_parser('a', help='a help')
parser_a.add_argument('bar', type=int, help='bar help')
# create the parser for the "b" command
parser_b = subparsers.add_parser('b', help='b help')
parser_b.add_argument('--baz', choices='XYZ', help='baz help')
parsed_args = parser.parse_args()
I was also able to print a short help for commands using _choices_actions
.
def print_help(parser):
print(parser.description)
print('\ncommands:\n')
# retrieve subparsers from parser
subparsers_actions = [
action for action in parser._actions
if isinstance(action, argparse._SubParsersAction)]
# there will probably only be one subparser_action,
# but better save than sorry
for subparsers_action in subparsers_actions:
# get all subparsers and print help
for choice in subparsers_action._choices_actions:
print(' {:<19} {}'.format(choice.dest, choice.help))