How to get character for a given ascii value

Question

How can I get the ascii character of a given ascii code.

e.g. I\'m looking for a method that given the code 65 would return \"A\".

Thanks

Answer 1

Sorry I dont know Java, but I was faced with the same problem tonight, so I wrote this (it's in c#)

public string IncrementString(string inboundString)    {
byte[] bytes = System.Text.Encoding.ASCII.GetBytes(inboundString.ToArray);
bool incrementNext = false;

for (l = -(bytes.Count - 1); l <= 0; l++) {
    incrementNext = false;

    int bIndex = Math.Abs(l);
    int asciiVal = Conversion.Val(bytes(bIndex).ToString);

    asciiVal += 1;

    if (asciiVal > 57 & asciiVal < 65)
        asciiVal = 65;
    if (asciiVal > 90) {
        asciiVal = 48;
        incrementNext = true;
    }

    bytes(bIndex) = System.Text.Encoding.ASCII.GetBytes({ Strings.Chr(asciiVal) })(0);

    if (incrementNext == false)
        break; // TODO: might not be correct. Was : Exit For
}

inboundString = System.Text.Encoding.ASCII.GetString(bytes);

return inboundString;
}

Answer 2

Simply Try this:

int n = Convert.ToInt32(Console.ReadLine());
Console.WriteLine("data is: {0}", Convert.ToChar(n));

Answer 3

Do you mean "A" (a string) or 'A' (a char)?

int unicode = 65;
char character = (char) unicode;
string text = character.ToString();

Note that I've referred to Unicode rather than ASCII as that's C#'s native character encoding; essentially each char is a UTF-16 code point.