How to get character for a given ascii value

Question

How can I get the ascii character of a given ascii code.

e.g. I\'m looking for a method that given the code 65 would return \"A\".

Thanks

Answer 1

There are a few ways to do this.

Using char struct (to string and back again)

string _stringOfA = char.ConvertFromUtf32(65);

int _asciiOfA = char.ConvertToUtf32("A", 0);

Simply casting the value (char and string shown)

char _charA = (char)65;

string _stringA = ((char)65).ToString();

Using ASCIIEncoding.
This can be used in a loop to do a whole array of bytes

var _bytearray = new byte[] { 65 };

ASCIIEncoding _asiiencode = new ASCIIEncoding();

string _alpha = _asiiencode .GetString(_newByte, 0, 1);

You can override the type converter class, this would allow you to do some fancy validation of the values:

var _converter = new ASCIIConverter();

string _stringA = (string)_converter.ConvertFrom(65);

int _intOfA = (int)_converter.ConvertTo("A", typeof(int));

Here is the Class:

public class ASCIIConverter : TypeConverter
{
    // Overrides the CanConvertFrom method of TypeConverter.
    // The ITypeDescriptorContext interface provides the context for the
    // conversion. Typically, this interface is used at design time to 
    // provide information about the design-time container.
    public override bool CanConvertFrom(ITypeDescriptorContext context,
       Type sourceType)
    {
        if (sourceType == typeof(string))
        {
            return true;
        }
        return base.CanConvertFrom(context, sourceType);
    }

    public override bool CanConvertTo(ITypeDescriptorContext context, Type destinationType)
    {
        if (destinationType == typeof(int))
        {
            return true;
        }
        return base.CanConvertTo(context, destinationType);
    }


    // Overrides the ConvertFrom method of TypeConverter.
    public override object ConvertFrom(ITypeDescriptorContext context,
       CultureInfo culture, object value)
    {

        if (value is int)
        {
            //you can validate a range of int values here
            //for instance 
            //if (value >= 48 && value <= 57)
            //throw error
            //end if

            return char.ConvertFromUtf32(65);
        }
        return base.ConvertFrom(context, culture, value);
    }

    // Overrides the ConvertTo method of TypeConverter.
    public override object ConvertTo(ITypeDescriptorContext context,
       CultureInfo culture, object value, Type destinationType)
    {
        if (destinationType == typeof(int))
        {
            return char.ConvertToUtf32((string)value, 0);
        }
        return base.ConvertTo(context, culture, value, destinationType);
    }
}

Answer 2

This works in my code.

string asciichar = (Convert.ToChar(65)).ToString();

Return: asciichar = 'A';

Answer 3

 string c = Char.ConvertFromUtf32(65);

c will contain "A"

Answer 4

It can also be done in some other manner

byte[] pass_byte = Encoding.ASCII.GetBytes("your input value");

and then print result. by using foreach loop.

Answer 5

I believe a simple cast can work

int ascii = (int) "A"

Answer 6

Here's a function that works for all 256 bytes, and ensures you'll see a character for each value:

static char asciiSymbol( byte val )
{
    if( val < 32 ) return '.';  // Non-printable ASCII
    if( val < 127 ) return (char)val;   // Normal ASCII
    // Workaround the hole in Latin-1 code page
    if( val == 127 ) return '.';
    if( val < 0x90 ) return "€.‚ƒ„…†‡ˆ‰Š‹Œ.Ž."[ val & 0xF ];
    if( val < 0xA0 ) return ".‘’“”•–—˜™š›œ.žŸ"[ val & 0xF ];
    if( val == 0xAD ) return '.';   // Soft hyphen: this symbol is zero-width even in monospace fonts
    return (char)val;   // Normal Latin-1
}