This has been asked several times for several languages but I can\'t get it to work. I have a string like this
String str = \"This is a string.\\nThis is a l
A little more robust version of what you're attempting:
str = str.replaceAll("(\r\n|\n\r|\r|\n)", "<br />");
It works for me. The Java code works exactly as you wrote it. In the tester, the input string should be:
This is a string.
This is a long string.
...with a real linefeed. You can't use:
This is a string.\nThis is a long string.
...because it treats \n
as the literal sequence backslash 'n'.
It works for me.
public class Program
{
public static void main(String[] args) {
String str = "This is a string.\nThis is a long string.";
str = str.replaceAll("(\r\n|\n)", "<br />");
System.out.println(str);
}
}
Result:
This is a string.<br />This is a long string.
Your problem is somewhere else.
This should work. You need to put in two slashes
str = str.replaceAll("(\\r\\n|\\n)", "<br />");
In this Reference, there is an example which shows
private final String REGEX = "\\d"; // a single digit
I have used two slashes in many of my projects and it seems to work fine!
That should work, but don't kill yourself trying to figure it out. Just use 2 passes.
str = str.replaceAll("(\r\n)", "<br />");
str = str.replaceAll("(\n)", "<br />");
Disclaimer: this is not very efficient.
For me, this worked:
rawText.replaceAll("(\\\\r\\\\n|\\\\n)", "\\\n");
Tip: use regex tester for quick testing without compiling in your environment