How can I print a quotation mark in C?

Question

In an interview I was asked

Print a quotation mark using the printf() function

I was overwhelmed. Even in their off

Answer 1

you should use escape character like this:

printf("\"");

Answer 2

#include<stdio.h>
int main(){
char ch='"';
printf("%c",ch);
return 0;
}

Output: "

Answer 3

Try this:

#include <stdio.h>

int main()
{
  printf("Printing quotation mark \" ");
}

Answer 4

Besides escaping the character, you can also use the format %c, and use the character literal for a quotation mark.

printf("And I quote, %cThis is a quote.%c\n", '"', '"');

Answer 5

You have to use escaping of characters. It's a solution of this chicken-and-egg problem: how do I write a ", if I need it to terminate a string literal? So, the C creators decided to use a special character that changes treatment of the next char:

printf("this is a \"quoted string\"");

Also you can use '\' to input special symbols like "\n", "\t", "\a", to input '\' itself: "\\" and so on.

Answer 6

Without a backslash, special characters have a natural special meaning. With a backslash they print as they appear.

\   -   escape the next character
"   -   start or end of string
’   -   start or end a character constant
%   -   start a format specification
\\  -   print a backslash
\"  -   print a double quote
\’  -   print a single quote
%%  -   print a percent sign

The statement

printf("  \"  "); 

will print you the quotes. You can also print these special characters \a, \b, \f, \n, \r, \t and \v with a (slash) preceeding it.