How do I remove http, https and slash from user input in php

Question

Example user input

http://domain.com/
http://domain.com/topic/
http://domain.com/topic/cars/
http://www.domain.com/topic/questions/

I want

Answer 1

if its the first characters in the string you can use substr(0,8) , and it will remove the first 8th character if its not use the "str_replace()" function http://php.net/manual/en/function.str-replace.php

Answer 2

You should use an array of "disallowed" terms and use strpos and str_replace to dynamically remove them from the passed-in URL:

function remove_http($url) {
   $disallowed = array('http://', 'https://');
   foreach($disallowed as $d) {
      if(strpos($url, $d) === 0) {
         return str_replace($d, '', $url);
      }
   }
   return $url;
}

Answer 3

Create an array:

$remove = array("http://","https://");

and replace with empty string:

str_replace($remove,"",$url);

it would look something like this:

function removeProtocol($url){
    $remove = array("http://","https://");
    return str_replace($remove,"",$url);
}

Str_replace will return a string if your haystack (input) is a string and you replace your needle(s) in the array with a string. It's nice so you can avoid all the extra looping.

Happy Coding!

Answer 4

You could use the parse url Functionality of PHP. This will work for all Protocols, even ftp:// or https://

Eiter get the Protocol Component and substr it from the Url, or just concatenate the other Parts back together ...

http://php.net/manual/de/function.parse-url.php

Answer 5

You can remove both https and http in one line using ereg_replace:

$url = ereg_replace("(https?)://", "", $url);

Answer 6

Found this http://refactormycode.com/codes/598-remove-http-from-url-string

function remove_http($url = '')
{
    if ($url == 'http://' OR $url == 'https://')
    {
        return $url;
    }
    $matches = substr($url, 0, 7);
    if ($matches=='http://') 
    {
        $url = substr($url, 7);     
    }
    else
    {
        $matches = substr($url, 0, 8);
        if ($matches=='https://') 
        $url = substr($url, 8);
    }
    return $url;
}