I have a textfile, let\'s call it goodlines.txt
and I want to load it and make a list that contains each line in the text file.
I tried using the
You are using str
methods on an open file object.
You can read the file as a list of lines by simply calling list()
on the file object:
with open('goodlines.txt') as f:
mylist = list(f)
This does include the newline characters. You can strip those in a list comprehension:
with open('goodlines.txt') as f:
mylist = [line.rstrip('\n') for line in f]
Try this:
>>> f = open('goodlines.txt')
>>> mylist = f.readlines()
open()
function returns a file object. And for file object, there is no method like splitlines()
or split()
. You could use dir(f)
to see all the methods of file object.
You're not reading the file content:
my_file_contents = f.read()
See the docs for further infos
You could, without calling read()
or readlines()
loop over your file object:
f = open('goodlines.txt')
for line in f:
print(line)
If you want a list out of it (without \n
as you asked)
my_list = [line.rstrip('\n') for line in f]