How can I cleanup the workspace in Jenkins? I am using AccuRev
as version control tool.
I created freestyle
projects in Jenkins.
There is an option to do it. Configure -> Post-build Actions
The option comes by default at least in Jenkins version 2.236
Beside above solutions, there is a more "COMMON" way - directly delete the largest space consumer from Linux machine. You can follow the below steps:
Using ls -lart to list out hidden folder also, normally jenkin installation is placed in .jenkins/ folder
[xxxxx ~]$ ls -lart drwxrwxr-x 12 xxxx 4096 Feb 8 02:08 .jenkins/
Use df -h
to show Disk space in high level
du -sh ./*/
to list out total memory for each subfolder in current path.
du -a /etc/ | sort -n -r | head -n 10
will list top 10 directories eating disk space in /etc/
Normally ./job/ folder or ./workspace/ folder can be the largest folder. Please go inside and delete base on you need (DO NOT delete entire folder).
rm -rf theFolderToDelete
IMPORTANT: It is safe to remove the workspace for a given Jenkins job as long as the job is not currently running!
NOTE: I am assuming your $JENKINS_HOME
is set to the default: /var/jenkins_home
.
rm -rf /var/jenkins_home/workspaces/<workspace>
rm -rf /var/jenkins_home/workspaces/*
This one uses grep to create a whitelist:
ls /var/jenkins_home/workspace \
| grep -v -E '(job-to-skip|another-job-to-skip)$' \
| xargs -I {} rm -rf /var/jenkins_home/workspace/{}
This one uses du and sort to list workspaces in order of largest to smallest. Then, it uses head to grab the first 10:
du -d 1 /var/jenkins_home/workspace \
| sort -n -r \
| head -n 10 \
| xargs -I {} rm -rf /var/jenkins_home/workspace/{}
You can run the below script in the Manage Jenkins → Scripts Console for deleting the workspaces of all the jobs at one shot. We did this to clean up space on the file system.
import hudson.model.*
// For each project
for(item in Hudson.instance.items) {
// check that job is not building
if(!item.isBuilding()) {
println("Wiping out workspace of job "+item.name)
item.doDoWipeOutWorkspace()
}
else {
println("Skipping job "+item.name+", currently building")
}
}
not allowed to comment, therefore:
The answer from Upen works just fine, but not if you have Jenkins Pipeline Jobs mixed with Freestyle Jobs. There is no such Method as DoWipeWorkspace on Pipeline Jobs. So I modified the Script in order to skip those:
import hudson.model.*
import org.jenkinsci.plugins.workflow.job.WorkflowJob
// For each project
for(item in Hudson.instance.items) {
// check that job is not building
if(!item.isBuilding() && !(item instanceof WorkflowJob))
{
println("Wiping out workspace of job "+item.name)
item.doDoWipeOutWorkspace()
}
else {
println("Skipping job "+item.name+", currently building")
}
}
you could also filter by Job Names if required:
item.getDisplayName().toLowerCase().contains("release")
Assuming the question is about cleaning the workspace of the current job, you can run:
test -n "$WORKSPACE" && rm -rf "$WORKSPACE"/*