Get JavaScript object from array of objects by value of property [duplicate]

Answer 1

var jsObjects = [{a: 1, b: 2}, {a: 3, b: 4}, {a: 5, b: 6}, {a: 7, b: 8}];

to access the third object, use: jsObjects[2];
to access the third object b value, use: jsObjects[2].b;

Answer 2

Using find with bind to pass specific key values to a callback function.

   function byValue(o) { 
       return o.a === this.a && o.b === this.b; 
   };   

   var result = jsObjects.find(byValue.bind({ a: 5, b: 6 }));

Answer 3

Filter array of objects, which property matches value, returns array:

var result = jsObjects.filter(obj => {
  return obj.b === 6
})

See the MDN Docs on Array.prototype.filter()

const jsObjects = [
  {a: 1, b: 2}, 
  {a: 3, b: 4}, 
  {a: 5, b: 6}, 
  {a: 7, b: 8}
]

let result = jsObjects.filter(obj => {
  return obj.b === 6
})

console.log(result)

Find the value of the first element/object in the array, otherwise undefined is returned.

var result = jsObjects.find(obj => {
  return obj.b === 6
})

See the MDN Docs on Array.prototype.find()

const jsObjects = [
  {a: 1, b: 2}, 
  {a: 3, b: 4}, 
  {a: 5, b: 6}, 
  {a: 7, b: 8}
]

let result = jsObjects.find(obj => {
  return obj.b === 6
})

console.log(result)

Answer 4

OK, there are few ways to do that, but let's start with the simplest one and latest approach to do this, this function is called find().

Just be careful when you using find to as even IE11 dosn't support it, so it needs to be transpiled...

so you have this object as you said:

var jsObjects = [
   {a: 1, b: 2}, 
   {a: 3, b: 4}, 
   {a: 5, b: 6}, 
   {a: 7, b: 8}
];

and you can write a function and get it like this:

function filterValue(obj, key, value) {
  return obj.find(function(v){ return v[key] === value});
}

and use the function like this:

filterValue(jsObjects, "b", 6); //{a: 5, b: 6}

Also in ES6 for even shortened version:

const filterValue = (obj, key, value)=> obj.find(v => v[key] === value);

This method only return the first value which match..., for better result and browser support, you can use filter:

const filterValue = (obj, key, value)=> obj.filter(v => v[key] === value);

and we will return [{a: 5, b: 6}]...

This method will return an array instead...

You simpley use for loop as well, create a function like this:

function filteredArray(arr, key, value) {
  const newArray = [];
  for(i=0, l=arr.length; i<l; i++) {
    if(arr[i][key] === value) {
      newArray.push(arr[i]);
    }
  }
 return newArray;
}

and call it like this:

filteredArray(jsObjects, "b", 6); //[{a: 5, b: 6}]

Answer 5

You can use it with the arrow function as well like as below :

var demoArray = [
   {name: 'apples', quantity: 2},
   {name: 'bananas', quantity: 0},
   {name: 'cherries', quantity: 5}
];

var result = demoArray.filter( obj => obj.name === 'apples')[0];
console.log(result);
// {name: 'apples', quantity: 2}