The intersection of two sorted arrays

Question

Given two sorted arrays: A and B. The size of array A is La and the size of array B is Lb. How

Answer 1

void Intersect()
{
    int la, lb;
    la = 5;
    lb = 100;
    int A[5];
    int i, j, k;
    i = j = k = 0;
    for (; i < 5; ++i)
        A[i] = i + 1;
    int B[100];
    for (; j < 100; ++j)
        B[j] = j + 2;
    int newSize = la < lb ? la : lb;
    int* C = new int[newSize];
    i = j = 0;
    for (; k < lb && i < la && j < lb; ++k)
    {
        if (A[i] < B[j])
            i++;
        else if (A[i] > B[j])
            j++;
        else
        {
            C[k] = A[i];
            i++;
            j++;
        }
    }
    for (k = 0; k < newSize; ++k)
        cout << C[k] << NEWLINE;
}

Answer 2

 //intersection of two arrays
#include<iostream>
using namespace std;
int main() {

int i=0,j=0,m,n;
int arr1[i],arr2[j];
cout<<"Enter the number of elements in array 1: ";
cin>> m;
cout<<"Enter the number of elements in array 2: ";
cin>>n;
for (i=0;i<m;i++){
    cin>> arr1[i];
}
for(j=0;j<n;j++){
    cin>> arr2[j];
}
for(j=0;j<n;j++){
    for(i=0;i<m;i++) {
        if (arr1[i] == arr2[j]){
        cout<< arr1[i];
        cout << ' ';
        break;
        }
    } 
 }    

 return 0;
 }