Is there any easy way or function to determine the greatest number in a python list? I could just code it, as I only have three numbers, however it would make the code a lot
This approach is without using
max()
function
a = [1,2,3,4,6,7,99,88,999]
max_num = 0
for i in a:
if i > max_num:
max_num = i
print(max_num)
Also if you want to find the index of the resulting max,
print(a.index(max_num))
Direct approach by using function max()
max() function returns the item with the highest value, or the item with the highest value in an iterable
Example: when you have to find max on integers/numbers
a = (1, 5, 3, 9)
print(max(a))
>> 9
Example: when you have string
x = max("Mike", "John", "Vicky")
print(x)
>> Vicky
It basically returns the name with the highest value, ordered alphabetically.
You can actually sort it:
sorted(l,reverse=True)
l = [1, 2, 3]
sort=sorted(l,reverse=True)
print(sort)
You get:
[3,2,1]
But still if want to get the max do:
print(sort[0])
You get:
3
if second max:
print(sort[1])
and so on...
You can use the inbuilt function max() with multiple arguments:
print max(1, 2, 3)
or a list:
list = [1, 2, 3]
print max(list)
or in fact anything iterable.
max
is a builtin function in python, which is used to get max value from a sequence, i.e (list, tuple, set, etc..)
print(max([9, 7, 12, 5]))
# prints 12
What about max()
highest = max(1, 2, 3) # or max([1, 2, 3]) for lists
Use max()
>>> l = [1, 2, 5]
>>> max(l)
5
>>>