Didn't Java once have a Pair class? [duplicate]

Answer 1

If you want a pair (not supposedly key-value pair) just to hold two generic data together neither of the solutions above really handy since first (or so called Key) cannot be changed (neither in Apache Commons Lang's Pair nor in AbstractMap.SimpleEntry). They have thier own reasons, but still you may need to be able to change both of the components. Here is a Pair class in which both elements can be set

public class Pair<First, Second> {
    private First first;
    private Second second;

    public Pair(First first, Second second) {
        this.first = first;
        this.second = second;
    }

    public void setFirst(First first) {
        this.first = first;
    }

    public void setSecond(Second second) {
        this.second = second;
    }

    public First getFirst() {
        return first;
    }

    public Second getSecond() {
        return second;
    }

    public void set(First first, Second second) {
        setFirst(first);
        setSecond(second);
    }

    @Override
    public boolean equals(Object o) {
        if (this == o) return true;
        if (o == null || getClass() != o.getClass()) return false;

        Pair pair = (Pair) o;

        if (first != null ? !first.equals(pair.first) : pair.first != null) return false;
        if (second != null ? !second.equals(pair.second) : pair.second != null) return false;

        return true;
    }

    @Override
    public int hashCode() {
        int result = first != null ? first.hashCode() : 0;
        result = 31 * result + (second != null ? second.hashCode() : 0);
        return result;
    }
}

Answer 2

No, but it's been requested many times.

Answer 3

There are lots of implementation around here, but all the time something is missing , the Override of equal and hash method.

here is a more complete version of this class:

/**
 * Container to ease passing around a tuple of two objects. This object provides a sensible
 * implementation of equals(), returning true if equals() is true on each of the contained
 * objects.
 */
public class Pair<F, S> {
    public final F first;
    public final S second;

    /**
     * Constructor for a Pair.
     *
     * @param first the first object in the Pair
     * @param second the second object in the pair
     */
    public Pair(F first, S second) {
        this.first = first;
        this.second = second;
    }

    /**
     * Checks the two objects for equality by delegating to their respective
     * {@link Object#equals(Object)} methods.
     *
     * @param o the {@link Pair} to which this one is to be checked for equality
     * @return true if the underlying objects of the Pair are both considered
     *         equal
     */
    @Override
    public boolean equals(Object o) {
        if (!(o instanceof Pair)) {
            return false;
        }
        Pair<?, ?> p = (Pair<?, ?>) o;
        return Objects.equals(p.first, first) && Objects.equals(p.second, second);
    }

    /**
     * Compute a hash code using the hash codes of the underlying objects
     *
     * @return a hashcode of the Pair
     */
    @Override
    public int hashCode() {
        return (first == null ? 0 : first.hashCode()) ^ (second == null ? 0 : second.hashCode());
    }

    /**
     * Convenience method for creating an appropriately typed pair.
     * @param a the first object in the Pair
     * @param b the second object in the pair
     * @return a Pair that is templatized with the types of a and b
     */
    public static <A, B> Pair <A, B> create(A a, B b) {
        return new Pair<A, B>(a, b);
    }
}

Answer 4

This should help.

To sum it up: a generic Pair class doesn't have any special semantics and you could as well need a Tripplet class etc. The developers of Java thus didn't include a generic Pair but suggest to write special classes (which isn't that hard) like Point(x,y), Range(start, end) or Map.Entry(key, value).