Generating a Random Hex Color in Python

Question

For a Django App, each \"member\" is assigned a color to help identify them. Their color is stored in the database and then printed/copied into the HTML when it is needed. T

Answer 1

import random

def hex_code_colors():
    a = hex(random.randrange(0,256))
    b = hex(random.randrange(0,256))
    c = hex(random.randrange(0,256))
    a = a[2:]
    b = b[2:]
    c = c[2:]
    if len(a)<2:
        a = "0" + a
    if len(b)<2:
        b = "0" + b
    if len(c)<2:
        c = "0" + c
    z = a + b + c
    return "#" + z.upper()

Answer 2

This has been done before. Rather than implementing this yourself, possibly introducing errors, you may want to use a ready library, for example Faker. Have a look at the color providers, in particular hex_digit.

In [1]: from faker import Factory

In [2]: fake = Factory.create()

In [3]: fake.hex_color()
Out[3]: u'#3cae6a'

In [4]: fake.hex_color()
Out[4]: u'#5a9e28'

Answer 3

hex_digits = ['0','1','2','3','4','5','6','7','8','9','a','b','c','d','e','f']

digit_array = []

for i in xrange(6):
    digit_array.append(hex_digits[randint(0,15)])
joined_digits = ''.join(digit_array)

color = '#' + joined_digits

Answer 4

Here is a simple way:

import random
color = "%06x" % random.randint(0, 0xFFFFFF)

To generate a random 3 char color:

import random
color = "%03x" % random.randint(0, 0xFFF)

%x in C-based languages is a string formatter to format integers as hexadecimal strings while 0x is the prefix to write numbers in base-16.

Colors can be prefixed with "#" if needed (CSS style)

Answer 5

Here's a simple code that I wrote based on what hexadecimal color notations represent:

import random 

def getRandomCol():

    r = hex(random.randrange(0, 255))[2:]
    g = hex(random.randrange(0, 255))[2:]
    b = hex(random.randrange(0, 255))[2:]

    random_col = '#'+r+g+b`enter code here`

    return random_col

The '#' in the hexadecimal color code just represents that the number represented is just a hexadecimal number. What's important is the next 6 digits. Pairs of 2 digits in those 6 hexadecimal digits represent the intensity of RGB (Red, Green, and Blue) each. The intensity of each color ranges between 0-255 and a combination of different intensities of RGB produces different colors.

For example, in #ff00ff, the first ff is equivalent to 255 in decimal, the next 00 is equivalent to 0 in decimal, and the last ff is equivalent to 255 in decimal. Therefore, #ff00ff in hexadecimal color coding is equivalent to RGB(255, 0, 255).

With this concept, here's the explanation of my approach:

1. Generated intensities of random numbers for each of r, g and b
2. Converted those intensities into hexadecimal
3. Ignored the first 2 characters of each hexadecimal value '0x'
4. Concatenated '#' with the hexadecimal values r, g and b intensities.

Feel free to refer to this link if you wanna know more about how colors work: https://hackernoon.com/hex-colors-how-do-they-work-d8cb935ac0f

Cheers!

Answer 6

import random

def get_random_hex:
    random_number = random.randint(0,16777215)

    # convert to hexadecimal
    hex_number = str(hex(random_number))

    # remove 0x and prepend '#'
    return'#'+ hex_number[2:]