Can I return to executing try-block after exception occurs? (The goal is to write less) For Example:
try:
do_smth1()
except:
pass
try:
do_smth2(
You can achieve what you want, but with a different syntax. You can use a "finally" block after the try/except. Doing this way, python will execute the block of code regardless the exception was thrown, or not.
Like this:
try:
do_smth1()
except:
pass
finally:
do_smth2()
But, if you want to execute do_smth2() only if the exception was not thrown, use a "else" block:
try:
do_smth1()
except:
pass
else:
do_smth2()
You can mix them too, in a try/except/else/finally clause. Have fun!
special_func to avoid try-except repetition:
def special_func(test_case_dict):
final_dict = {}
exception_dict = {}
def try_except_avoider(test_case_dict):
try:
for k,v in test_case_dict.items():
final_dict[k]=eval(v) #If no exception evaluate the function and add it to final_dict
except Exception as e:
exception_dict[k]=e #extract exception
test_case_dict.pop(k)
try_except_avoider(test_case_dict) #recursive function to handle remaining functions
finally: #cleanup
final_dict.update(exception_dict)
return final_dict #combine exception dict and final dict
return try_except_avoider(test_case_dict)
Run code:
def add(a,b):
return (a+b)
def sub(a,b):
return (a-b)
def mul(a,b):
return (a*b)
case = {"AddFunc":"add(8,8)","SubFunc":"sub(p,5)","MulFunc":"mul(9,6)"}
solution = special_func(case)
Output looks like:
{'AddFunc': 16, 'MulFunc': 54, 'SubFunc': NameError("name 'p' is not defined")}
To convert to variables:
locals().update(solution)
Variables would look like:
AddFunc = 16, MulFunc = 54, SubFunc = NameError("name 'p' is not defined")
I don't think you want to do this. The correct way to use a try
statement in general is as precisely as possible. I think it would be better to do:
try:
do_smth1()
except Stmnh1Exception:
# handle Stmnh1Exception
try:
do_smth2()
except Stmnh2Exception:
# handle Stmnh2Exception