Is it possible to do this on one line in Python?
if :
myList.append(\'myString\')
I have tried the ternary operator:
The reason the language doesn't allow you to use the syntax
variable = "something" if a_condition
without else
is that, in the case where a_condition == False
, variable
is suddenly unknown. Maybe it could default to None
, but Python requires that all variable assignments actually result in explicit assignments. This also applies to cases such as your function call, as the value passed to the function is evaluated just as the RHS of an assignment statement would be.
Similarly, all return
s must actually return, even if they are conditional return
s. Eg:
return variable if a_condition
is not allowed, but
return variable if a_condition else None
is allowed, since the second example is guaranteed to explicitly return something.
myList.extend(['myString'] if condition else [])
would also work, though it's more work than the other solutions.
Yes, you can do this:
<condition> and myList.append('myString')
If <condition>
is false, then short-circuiting will kick in and the right-hand side won't be evaluated. If <condition>
is true, then the right-hand side will be evaluated and the element will be appended.
I'll just point out that doing the above is quite non-pythonic, and it would probably be best to write this, regardless:
if <condition>: myList.append('myString')
Demonstration:
>>> myList = []
>>> False and myList.append('myString')
False
>>> myList
[]
>>> True and myList.append('myString')
>>> myList
['myString']
i’d just do this if i wanna add optional elements to a list based on a condition.
nums = [
1,
2,
3 if <condition> else None,
4,
]
nums = [i for i in nums if i is not None]
this just replaces the value with None if the condition is not met and then later, it just redefines the list without the None Values. this way they preserve their index if the condition is met
if <condition>: myList.append('myString')
Otherwise, no. Why the need to put it on one line?
Note that the "ternary operator" is an operator. Like any operator, it must return something, so how can you have a ternary operator without the else
clause? What is it supposed to return if the condition isn't true-like?
You are basically asking for do_thing() if <condition> else pass
construct (which will throw SyntaxError
, if ran). As I have discovered during research for (somewhat) similar question do_thing() if condition else None
is as close as you can get (which is just another way to do <condition> and do_thing()
). So, to summarize this idea and other answers, here are your options:
if <condition>: myList.append('myString')
— seems to be the least 'hacky' (and thus preferred) way<condition> and myList.append('myString')
myList.append('myString') if <condition> else None