I want to get last month\'s date. I wrote this out:
$prevmonth = date(\'M Y\');
Which gives me the current month/year. I can\'t tell if I
It's simple to get last month date
echo date("Y-n-j", strtotime("first day of previous month"));
echo date("Y-n-j", strtotime("last day of previous month"));
at November 3 returns
2014-10-1
2014-10-31
Use this short code to get previous month for any given date:
$tgl = '25 january 2012';
$prevmonth = date("M Y",mktime(0,0,0,date("m", strtotime($tgl))-1,1,date("Y", strtotime($tgl))));
echo $prevmonth;
The result is December 2011. Works on a month with shorter day with previous month.
$time = mktime(0, 0, 0, date("m"),date("d")-date("t"), date("Y"));
$lastMonth = date("d-m-Y", $time);
OR
$lastMonth = date("m-Y", mktime() - 31*3600*24);
works on 30.03.2012
The best solution I have found is this:
function subtracMonth($currentMonth, $monthsToSubtract){
$finalMonth = $currentMonth;
for($i=0;$i<$monthsToSubtract;$i++) {
$finalMonth--;
if ($finalMonth=='0'){
$finalMonth = '12';
}
}
return $finalMonth;
}
So if we are in 3(March) and we want to subtract 5 months that would be
subtractMonth(3,5);
which would give 10(October). If the year is also desired, one could do this:
function subtracMonth($currentMonth, $monthsToSubtract){
$finalMonth = $currentMonth;
$totalYearsToSubtract = 0;
for($i=0;$i<$monthsToSubtract;$i++) {
$finalMonth--;
if ($finalMonth=='0'){
$finalMonth = '12';
$totalYearsToSubtract++;
}
}
//Get $currentYear
//Calculate $finalYear = $currentYear - $totalYearsToSubtract
//Put resulting $finalMonth and $finalYear into an object as attributes
//Return the object
}
Found this one wrong when the previous months is shorter than current.
echo date("Y-m-d H:i:s",strtotime("-1 month"));
Try on March the 30th and you will get 2012-03-01 instead of 2012-02...
Working out on better solution...
You can use strtotime, which is great in this kind of situations :
$timestamp = strtotime('-1 month');
var_dump(date('Y-m', $timestamp));
Will get you :
string '2009-11' (length=7)