I was wondering how I can get the current device orientation in Swift? I know there are examples for Objective-C, however I haven\'t been able to get it working in Swift.
you can use:
override func didRotateFromInterfaceOrientation(fromInterfaceOrientation: UIInterfaceOrientation) {
var text=""
switch UIDevice.currentDevice().orientation{
case .Portrait:
text="Portrait"
case .PortraitUpsideDown:
text="PortraitUpsideDown"
case .LandscapeLeft:
text="LandscapeLeft"
case .LandscapeRight:
text="LandscapeRight"
default:
text="Another"
}
NSLog("You have moved: \(text)")
}
SWIFT 3 UPDATE
override func didRotate(from fromInterfaceOrientation: UIInterfaceOrientation) {
var text=""
switch UIDevice.current.orientation{
case .portrait:
text="Portrait"
case .portraitUpsideDown:
text="PortraitUpsideDown"
case .landscapeLeft:
text="LandscapeLeft"
case .landscapeRight:
text="LandscapeRight"
default:
text="Another"
}
NSLog("You have moved: \(text)")
}
or
override func willRotateToInterfaceOrientation(toInterfaceOrientation: UIInterfaceOrientation, duration: NSTimeInterval) {
}
with Notification you can check: IOS8 Swift: How to detect orientation change?
NOTE : didRotateFromInterfaceOrientation is Deprecated Use viewWillTransitionToSize for iOS 2.0 and later
In case of Face up and Face Down this will not work. So we need to use the following.
if UIApplication.shared.statusBarOrientation.isLandscape {
// activate landscape changes
} else {
// activate portrait changes
}
So, if Apple is deprecating the whole orientation string thing ("portrait","landscape"), then all you care about is the ratio of width to height. (kinda like @bpedit's answer)
When you divide the width by the height, if the result is less than 1, then the mainScreen or container or whatever is in "portrait" "mode". If the result is greater than 1, it's a "landscape" painting. ;)
override func viewWillAppear(animated: Bool) {
let size: CGSize = UIScreen.mainScreen().bounds.size
if size.width / size.height > 1 {
print("landscape")
} else {
print("portrait")
}
}
override func viewWillTransitionToSize(size: CGSize, withTransitionCoordinator coordinator: UIViewControllerTransitionCoordinator) {
if size.width / size.height > 1 {
print("landscape")
} else {
print("portrait")
}
}
(I'm guessing that if you use this approach then you probably don't really care about specifically handling the condition when the ratio is exactly 1, equal width and height.)
I found that the alternative code in Swift for the Obj-C code
if (UIInterfaceOrientationIsLandscape([UIApplication sharedApplication].statusBarOrientation))
is
if UIApplication.shared.statusBarOrientation.isLandscape
Note: we are trying to find the status bar orientation is landscape or not. If it is landscape then the if statement is true.
To find current device orientation simply use this code:
UIApplication.sharedApplication().statusBarOrientation
for swift 3.0
UIApplication.shared.statusBarOrientation
override func willRotateToInterfaceOrientation(toInterfaceOrientation: UIInterfaceOrientation, duration: NSTimeInterval) {
if (toInterfaceOrientation.isLandscape) {
NSLog("Landscape");
}
else {
NSLog("Portrait");
}
}
To get the status bar (and therefor UI) orientation like the Objective-C code you have, it's simply:
UIApplication.sharedApplication().statusBarOrientation
You can also use the orientation property of UIDevice:
UIDevice.currentDevice().orientation
However, that may not match what orientation your UI is in. From the docs:
The value of the property is a constant that indicates the current orientation of the device. This value represents the physical orientation of the device and may be different from the current orientation of your application’s user interface. See “UIDeviceOrientation” for descriptions of the possible values.