MethodInvoker vs Action for Control.BeginInvoke

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走了就别回头了
走了就别回头了 2020-11-28 22:33

Which is more correct and why?

Control.BeginInvoke(new Action(DoSomething), null);

private void DoSomething()
{
    MessageBox.Show(\"What a great post\");
         


        
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  • 2020-11-28 22:51

    Action is defined in System, while MethodInvoker is defined in System.Windows.Forms - you may be better off using Action, since it is portable to other places. You will also find more places that accept Action as a parameter than MethodInvoker.

    However, the documentation does indicate that calls to delegates of type EventHandler or MethodInvoker in Control.Invoke() will be faster than any other type.

    Aside from which namepsace they are in, I don't believe there is a meaningful functional difference between Action and MethodInvoker - they are essentially both defined as:

    public delegate void NoParamMethod();
    

    As an aside, Action has several overloads which allow parameters to be passed in - and it is generic so that they can be typesafe.

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  • 2020-11-28 22:53

    It is a matter of preference in most cases, unless you intend to reuse the DoSomething() method. Also the anonymous functions will place your scoped variables on the heap, might make it a more expensive function.

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  • 2020-11-28 22:55

    Don't forget to somehow check if control is available at the moment, to avoid errors at closing form.

    if(control.IsHandleCreated)
    control.BeginInvoke((MethodInvoker)(() => control.Text="check123"));
    
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  • 2020-11-28 22:59

    Also per MSDN:

    MethodInvoker provides a simple delegate that is used to invoke a method with a void parameter list. This delegate can be used when making calls to a control's Invoke method, or when you need a simple delegate but do not want to define one yourself.

    an Action on the other hand can take up to 4 parameters.

    But I don't think there is any difference between MethodInvoker and Action as they both simply encapsulate a delegate that doesn't take a paremter and returns void

    If you look at their definitions you'll simply see this.

    public delegate void MethodInvoker();
    public delegate void Action();
    

    btw you could also write your second line as.

    Control.BeginInvoke(new MethodInvoker(DoSomething), null);
    
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  • 2020-11-28 23:00

    For each solution bellow I run a 131072 (128*1024) iterations (in one separated thread). The VS2010 performance assistant give this results:

    • read-only MethodInvoker: 5664.53 (+0%)
    • New MethodInvoker: 5828.31 (+2.89%)
    • function cast in MethodInvoker: 5857.07 (+3.40%)
    • read-only Action: 6467.33 (+14.17%)
    • New Action: 6829.07 (+20.56%)

    Call to a new Action at each iteration

        private void SetVisibleByNewAction()
        {
            if (InvokeRequired)
            {
                Invoke(new Action(SetVisibleByNewAction));
            }
            else
            {
                Visible = true;
            }
        }
    

    Call to a read-only, build in constructor, Action at each iteration

        // private readonly Action _actionSetVisibleByAction
        // _actionSetVisibleByAction= SetVisibleByAction;
        private void SetVisibleByAction()
        {
            if (InvokeRequired)
            {
                Invoke(_actionSetVisibleByAction);
            }
            else
            {
                Visible = true;
            }
        }
    

    Call to a new MethodInvoker at each iteration.

        private void SetVisibleByNewMethodInvoker()
        {
            if (InvokeRequired)
            {
                Invoke(new MethodInvoker(SetVisibleByNewMethodInvoker));
            }
            else
            {
                Visible = true;
            }
        }
    

    Call to a read-only, build in constructor, MethodInvoker at each iteration

        // private readonly MethodInvoker _methodInvokerSetVisibleByMethodInvoker 
        // _methodInvokerSetVisibleByMethodInvoker = SetVisibleByMethodInvoker;
        private void SetVisibleByMethodInvoker()
        {
            if (InvokeRequired)
            {
                Invoke(_methodInvokerSetVisibleByMethodInvoker);
            }
            else
            {
                Visible = true;
            }
        }
    

    Call to the function cast in MethodInvoker at each iteration

        private void SetVisibleByDelegate()
        {
            if (InvokeRequired)
            {
                Invoke((MethodInvoker) SetVisibleByDelegate);
            }
            else
            {
                Visible = true;
            }
        }
    

    Example of call for the "New Action" solution :

        private void ButtonNewActionOnClick(object sender, EventArgs e)
        {
            new Thread(TestNewAction).Start();
        }
    
        private void TestNewAction()
        {
            var watch = Stopwatch.StartNew();
            for (var i = 0; i < COUNT; i++)
            {
                SetVisibleByNewAction();
            }
            watch.Stop();
            Append("New Action: " + watch.ElapsedMilliseconds + "ms");
        }
    
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  • 2020-11-28 23:03

    Both are equally correct, but the documentation for Control.Invoke states that:

    The delegate can be an instance of EventHandler, in which case the sender parameter will contain this control, and the event parameter will contain EventArgs.Empty. The delegate can also be an instance of MethodInvoker, or any other delegate that takes a void parameter list. A call to an EventHandler or MethodInvoker delegate will be faster than a call to another type of delegate.

    So MethodInvoker would be a more efficient choice.

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