Is there a short and sweet way to generate a List
, or perhaps an Integer[]
or int[]
, with sequential values from some
You can use the Interval class from Eclipse Collections.
List<Integer> range = Interval.oneTo(10);
range.forEach(System.out::print); // prints 12345678910
The Interval
class is lazy, so doesn't store all of the values.
LazyIterable<Integer> range = Interval.oneTo(10);
System.out.println(range.makeString(",")); // prints 1,2,3,4,5,6,7,8,9,10
Your method would be able to be implemented as follows:
public List<Integer> makeSequence(int begin, int end) {
return Interval.fromTo(begin, end);
}
If you would like to avoid boxing ints as Integers, but would still like a list structure as a result, then you can use IntList with IntInterval from Eclipse Collections.
public IntList makeSequence(int begin, int end) {
return IntInterval.fromTo(begin, end);
}
IntList
has the methods sum()
, min()
, minIfEmpty()
, max()
, maxIfEmpty()
, average()
and median()
available on the interface.
Update for clarity: 11/27/2017
An Interval
is a List<Integer>
, but it is lazy and immutable. It is extremely useful for generating test data, especially if you deal a lot with collections. If you want you can easily copy an interval to a List
, Set
or Bag
as follows:
Interval integers = Interval.oneTo(10);
Set<Integer> set = integers.toSet();
List<Integer> list = integers.toList();
Bag<Integer> bag = integers.toBag();
An IntInterval
is an ImmutableIntList
which extends IntList
. It also has converter methods.
IntInterval ints = IntInterval.oneTo(10);
IntSet set = ints.toSet();
IntList list = ints.toList();
IntBag bag = ints.toBag();
An Interval
and an IntInterval
do not have the same equals
contract.
Update for Eclipse Collections 9.0
You can now create primitive collections from primitive streams. There are withAll
and ofAll
methods depending on your preference. If you are curious, I explain why we have both here. These methods exist for mutable and immutable Int/Long/Double Lists, Sets, Bags and Stacks.
Assert.assertEquals(
IntInterval.oneTo(10),
IntLists.mutable.withAll(IntStream.rangeClosed(1, 10)));
Assert.assertEquals(
IntInterval.oneTo(10),
IntLists.immutable.withAll(IntStream.rangeClosed(1, 10)));
Note: I am a committer for Eclipse Collections
You could use Guava Ranges
You can get a SortedSet
by using
ImmutableSortedSet<Integer> set = Ranges.open(1, 5).asSet(DiscreteDomains.integers());
// set contains [2, 3, 4]