How does Python importing exactly work?

Question

I have two specific situations where I don\'t understand how importing works in Python:

1st specific situation:

When I import the same modul

Answer 1

To answer your first question:

No, python does not get 'imported' twice. When python loads a module, it checks for the module in sys.modules. If it is not in there, it is put in there, and loaded.

To answer your second question:

Modules can define what names they will export to a from camelot import * scenario, and the behavior is to create names for the existing values, not to reference existing variables (python does not have references).

On a somewhat related topic, doing a from camelot import * is not the same as a regular import.

Answer 2

Part 1

The module is only loaded once, so there is no performance loss by importing it again. If you actually wanted it to be loaded/parsed again, you'd have to reload() the module.

The first place checked is sys.modules, the cache of all modules that have been imported previously. ^[source]

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Part 2

from foo import * imports a to the local scope. When assigning a value to a, it is replaced with the new value - but the original foo.a variable is not touched.

So unless you import foo and modify foo.a, both calls will return the same value.

For a mutable type such as a list or dict it would be different, modifying it would indeed affect the original variable - but assigning a new value to it would still not modify foo.whatever.

If you want some more detailed information, have a look at http://docs.python.org/reference/executionmodel.html:

The following constructs bind names: formal parameters to functions, import statements, class and function definitions (these bind the class or function name in the defining block), and targets that are identifiers if occurring in an assignment, for loop header, in the second position of an except clause header or after as in a with statement.

The two bold sections are the relevant ones for you: First the name a is bound to the value of foo.a during the import. Then, when doing a = 5, the name a is bound to 5. Since modifying a list/dict does not cause any binding, those operations would modify the original one (b and foo.b are bound to the same object on which you operate). Assigning a new object to b would be a binding operation again and thus separate b from foo.b.

It is also worth noting what exactly the import statement does:

• import foo binds the module name to the module object in the current scope, so if you modify foo.whatever, you will work with the name in that module - any modifications/assignments will affect the variable in the module.
• from foo import bar binds the given name(s) only (i.e. foo will remain unbound) to the element with the same name in foo - so operations on bar behave like explained earlier.
• from foo import * behaves like the previous one, but it imports all global names which are not prefixed with an underscore. If the module defines __all__ only names inside this sequence are imported.

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Part 3 (which doesn't even exist in your question :p)

The python documentation is extremely good and usually verbose - you find answer on almost every possible language-related question in there. Here are some useful links:

• http://docs.python.org/reference/datamodel.html (classes, properties, magic methods, etc.) ()
• http://docs.python.org/reference/executionmodel.html (how variables work in python)
• http://docs.python.org/reference/expressions.html
• http://docs.python.org/reference/simple_stmts.html (statements such as import, yield)
• http://docs.python.org/reference/compound_stmts.html (block statements such as for, try, with)