How to select date without time in SQL

Question

When I select date in SQL it is returned as 2011-02-25 21:17:33.933. But I need only the Date part, that is 2011-02-25. How can I do this?

Answer 1

The fastest is datediff, e.g.

select dateadd(d, datediff(d,0, [datecolumn]), 0), other..
from tbl

But if you only need to use the value, then you can skip the dateadd, e.g.

select ...
WHERE somedate <= datediff(d, 0, getdate())

where the expression datediff(d, 0, getdate()) is sufficient to return today's date without time portion.

Answer 2

If you want to return a date type as just a date use

CONVERT(date, SYSDATETIME())

or

SELECT CONVERT(date,SYSDATETIME()) 

or

DECLARE @DateOnly Datetime
SET @DateOnly=CONVERT(date,SYSDATETIME())

Answer 3

Use CAST(GETDATE() as date) that worked for me, simple.

Answer 4

you can use like this

SELECT Convert(varchar(10), GETDATE(),120) 

Answer 5

It's a bit late, but use the ODBC "curdate" function (angle brackes 'fn' is the ODBC function escape sequence).

SELECT {fn curdate()} 

Output: 2013-02-01