How to select date without time in SQL

Question

When I select date in SQL it is returned as 2011-02-25 21:17:33.933. But I need only the Date part, that is 2011-02-25. How can I do this?

Answer 1

Its too late but following worked for me well

declare @vCurrentDate date=getutcdate()

select @vCurrentDate

When data type is date, hours would be truncated

Answer 2

In PLSQL you can use

to_char(SYSDATE,'dd/mm/yyyy')

Answer 3

In case if you need the time to be zeros like 2018-01-17 00:00:00.000:

SELECT CONVERT(DATETIME, CONVERT(DATE, GETDATE()), 121)

Answer 4

Use is simple:

convert(date, Btch_Time)

Example below:

Table:

Efft_d       Loan_I  Loan_Purp_Type_C   Orig_LTV    Curr_LTV    Schd_LTV    Un_drwn_Bal_a      Btch_Time            Strm_I  Btch_Ins_I
2014-05-31  200312500   HL03             NULL         1.0000    1.0000         1.0000      2014-06-17 11:10:57.330  1005    24851e0a-53983699-14b4-69109

Select * from helios.dbo.CBA_SRD_Loan where Loan_I in ('200312500') and convert(date, Btch_Time) = '2014-06-17'

Answer 5

For SQL Server 2008:

Convert(date, getdate())  

Please refer to https://docs.microsoft.com/en-us/sql/t-sql/functions/getdate-transact-sql

Answer 6

CAST(
        FLOOR( 
             CAST( GETDATE() AS FLOAT ) 
        )

AS DATETIME
)

http://www.bennadel.com/blog/122-Getting-Only-the-Date-Part-of-a-Date-Time-Stamp-in-SQL-Server.htm