sort dict by value python [duplicate]

Answer 1

In your comment in response to John, you suggest that you want the keys and values of the dictionary, not just the values.

PEP 256 suggests this for sorting a dictionary by values.

import operator
sorted(d.iteritems(), key=operator.itemgetter(1))

If you want descending order, do this

sorted(d.iteritems(), key=itemgetter(1), reverse=True)

Answer 2

To get the values use

sorted(data.values())

To get the matching keys, use a key function

sorted(data, key=data.get)

To get a list of tuples ordered by value

sorted(data.items(), key=lambda x:x[1])

Related: see the discussion here: Dictionaries are ordered in Python 3.6+

Answer 3

If you actually want to sort the dictionary instead of just obtaining a sorted list use collections.OrderedDict

>>> from collections import OrderedDict
>>> from operator import itemgetter
>>> data = {1: 'b', 2: 'a'}
>>> d = OrderedDict(sorted(data.items(), key=itemgetter(1)))
>>> d
OrderedDict([(2, 'a'), (1, 'b')])
>>> d.values()
['a', 'b']