I want to create a directory if it does\'nt exist already.
Is using is_dir
enough for that purpose?
if ( !is_dir( $dir ) ) {
mkdir(
This is an old, but still topical question. Just test with the is_dir()
or file_exists()
function for the presence of the .
or ..
file in the directory under test. Each directory must contain these files:
is_dir("path_to_directory/.");
A way to check if a path is directory can be following:
function isDirectory($path) {
$all = @scandir($path);
return $all !== false;
}
NOTE: It will return false for non-existant path too, but works perfectly for UNIX/Windows
$save_folder = "some/path/" . date('dmy');
if (!file_exists($save_folder)) {
mkdir($save_folder, 0777);
}
Second variant in question post is not ok, because, if you already have file with the same name, but it is not a directory, !file_exists($dir)
will return false
, folder will not be created, so error "failed to open stream: No such file or directory"
will be occured. In Windows there is a difference between 'file' and 'folder' types, so need to use file_exists()
and is_dir()
at the same time, for ex.:
if (file_exists('file')) {
if (!is_dir('file')) { //if file is already present, but it's not a dir
//do something with file - delete, rename, etc.
unlink('file'); //for example
mkdir('file', NEEDED_ACCESS_LEVEL);
}
} else { //no file exists with this name
mkdir('file', NEEDED_ACCESS_LEVEL);
}
$year = date("Y");
$month = date("m");
$filename = "../".$year;
$filename2 = "../".$year."/".$month;
if(file_exists($filename)){
if(file_exists($filename2)==false){
mkdir($filename2,0777);
}
}else{
mkdir($filename,0777);
}
This is how I do
if(is_dir("./folder/test"))
{
echo "Exist";
}else{
echo "Not exist";
}